Skylight_lady Posted January 5, 2011 Share Posted January 5, 2011 Hi, I have a webpage that the super administrator log's into. Once the super administrator is logged in he/she can view his/her clients. The super admins clients also have their own clients, once the super admins clients login they can view their own clients details who register with them. What i am trying to do is have a link on that clients name (for the super admins clients) that will bring me to a new page where i can edit his/her details that is stored in the mysql database. I have used INPUT buttons for each clients row in a FORM which works......but i know this is not the right way to do it. This is the code i have used to display the clients with the input button: <?php $query = "SELECT ID FROM clients WHERE username = '$username'"; $result = mysql_query($query); if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)){ $userID = $row['ID']; $query = "SELECT * FROM users WHERE userID = '$userID'"; $result = mysql_query($query); $num=mysql_numrows($result); mysql_close(); ?> <table border="0" cellspacing="3" cellpadding="3" width="100%"> <tr> <th width="30%"><font face="Arial, Helvetica, sans-serif">Name</font></th> <th><font face="Arial, Helvetica, sans-serif">Username</font></th> <th><font face="Arial, Helvetica, sans-serif">Email Address</font></th> <th> </th> </tr> <?php $i=0; while ($i < $num) { $userID=mysql_result($result,$i,"userID"); $name=mysql_result($result,$i,"name"); $username=mysql_result($result,$i,"username"); $email=mysql_result($result,$i,"email"); ?> <tr> <td width="30%"><?php echo $name; ?></td> <td><?php echo $username; ?></td> <td><?php echo $email; ?></td> <td><form action="http://localhost/single-client.php?userID=<?php echo $userID; ?>&name=<?php echo $name; ?>" method="post" style="margin:0px;"> <input type="hidden" name="selectuser" id="selectuser" value="<?php echo $userID; ?>" /><input type="hidden" name="username1" id="username1" value="<?php echo $username; ?>" /><input type="hidden" name="name1" id="name1" value="<?php echo $name; ?>" /><input type="submit" name="submit" value="View Info" class="button" /></form></td> </tr> <?php $i++; }}} ?> </table> From the above code when i use the following code: ?userID=<?php echo $userID; ?>&name=<?php echo $name; ?> It doesn't make a difference .... it just displays the correct userID and name in the link. Once the INPUT button is clicked it will bring you to this page: <?php $query = "SELECT * FROM users WHERE userID = '".$_POST['selectuser']."' AND username = '".$_POST['username1']."'"; $result = mysql_query($query); if(mysql_num_rows($result)) { $userID = $_POST['selectuser']; while($row = mysql_fetch_assoc($result)){ $name = $row['name']; $userID = $row['userID']; $email = $row['email']; $username = $row['username']; $registered = $row['registered']; $last = $row['last']; ?> <?php echo $brokerID; ?> <table border="0" cellspacing="3" cellpadding="3" width="100%" summary="Client table"> <tr> <td><form action="http://localhost/single-client.php?userID=<?php echo $userID; ?>&name=<?php echo $name; ?>" method="post" style="margin:0px;"> <input type="hidden" name="selectuser" id="selectuser" value="<?php echo $userID; ?>" /><input type="hidden" name="username1" id="username1" value="<?php echo $username; ?>" /><input type="hidden" name="name1" id="name1" value="<?php echo $name; ?>" /><input type="submit" name="submit" value="Income" class="button" /></form></td> <td><form action="http://localhost/single-client.php?userID=<?php echo $userID; ?>&name=<?php echo $name; ?>" method="post" style="margin:0px;"> <input type="hidden" name="selectuser" id="selectuser" value="<?php echo $userID; ?>" /><input type="hidden" name="username1" id="username1" value="<?php echo $username; ?>" /><input type="hidden" name="name1" id="name1" value="<?php echo $name; ?>" /><input type="submit" name="submit" value="Bills" class="button" /></form></td> </tr> </table> <h2>Client Profile - <?php echo $_POST['name1']; ?></h2> <table border="0" cellspacing="3" cellpadding="3" width="100%"> <tr> <th><font face="Arial, Helvetica, sans-serif">Name</font></th> <th><font face="Arial, Helvetica, sans-serif">Username</font></th> <th><font face="Arial, Helvetica, sans-serif">Email Address</font></th> <th><font face="Arial, Helvetica, sans-serif">Registered</font></th> <th><font face="Arial, Helvetica, sans-serif">Last</font></th> </tr> <tr> <td><?php echo $name; ?></td> <td><?php echo $username; ?></td> <td><?php echo $email; ?></td> <td><?php echo $registered; ?></td> <td><?php echo $last; ?></td> </tr> </table> <?php } } else { echo "<p>Error</p>"; } ?> This page displays the correct user info. Is there a way to do it differently instead of using FORMS and INPUT buttons? and rather using links? Any help would be greatly appreciated. Link to comment https://forums.phpfreaks.com/topic/223433-how-to-edit-data-from-database-in-webpage/ Share on other sites More sharing options...
joel24 Posted January 5, 2011 Share Posted January 5, 2011 you can send the variables in the URL and have a link/image for the user to click. Then retrieve with $_GET i.e. page1 $sql = @mysql_query("SELECT userID, name FROM users WHERE company='4'"); while ($row = mysql_fetch_array($query)) { echo "<p><b>{$row['name']}</b><br/> echo "<a href='editPage.php?user={$row['user']}'>Edit User</a>"; echo '</p>'; } then on editPage.php $userID = mysql_real_escape_string($_GET['user']); $sql = @mysql_query("SELECT //do whatever you'll have to ensure the logged in user is allowed to edit/modify the selected user on the editPage.php, by using session variables etc Link to comment https://forums.phpfreaks.com/topic/223433-how-to-edit-data-from-database-in-webpage/#findComment-1155027 Share on other sites More sharing options...
Skylight_lady Posted January 5, 2011 Author Share Posted January 5, 2011 Thank you very much. Exactly what i wanted. Thanks again. Link to comment https://forums.phpfreaks.com/topic/223433-how-to-edit-data-from-database-in-webpage/#findComment-1155330 Share on other sites More sharing options...
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