AJLX Posted January 7, 2011 Share Posted January 7, 2011 Hello Guys, I have a column named message_status it can only have the values "read" or "unread" in it. I would like to show an image in the column next to it. If the message is "read" then I would like to display a green dot, and if it is unread I would like to display a red dot. I would also like to be able to have anything in the row that's "unread" to appear in bold. I completely stumped by this! I have written the following code, which doesn't seem to work, presumably because it is run after the table has been displayed? I am very new to this so please be gentle! Regards, AJLX $result = mysql_query("SELECT * FROM messages where username ='$username'ORDER BY {$_GET['orderbycol']} $sort"); echo "<table border='1'> <tr width='200'> <th>View</th> // code to display table removed </tr>"; $green_dot = $message_status; $red_dot = $message_status; $green = ""; $red = ""; $bold = ""; while ($row = mysql_fetch_array($result)) { echo "<tr>"; $id = $row['ID']; echo "<td><a href='/view_message.php/?view_message=$id'>View</a></td>"; echo "<td>" .$green . $red."</td>"; echo "<td>" .$bold . $message_status = $row['message_status'] . "</td>"; echo "<td>" .$bold. $row['date_sent'] . "</td>"; echo "<td>" .$bold. $row['contact_name'] . "</td>"; echo "<td>" .$bold. $row['subject'] . "</td>"; echo "</tr>"; } if ($green_dot = 'read'){ $green ='<img src=\"assets/red.jpg\"/>'; echo $green; } else { $red ='<img src=\"assets/red.jpg\"/>'; $bold = "<b>"; echo $red; Quote Link to comment https://forums.phpfreaks.com/topic/223721-variable-in-database-result/ Share on other sites More sharing options...
dropkick_pdx Posted January 7, 2011 Share Posted January 7, 2011 Something more like this should get the image you want to display. Your loop doesn't know about the bit after it. (if ($green_dot = 'read')...) You could use a simliar conditional to drop bold tags if that's how you'd like to do it as well. Using CSS to hit the whole row might be a little tidier, though. echo "<table border='1'> <tr width='200'> <th>View</th> // code to display table removed </tr>"; while ($row = mysql_fetch_array($result)) { echo "<tr>"; $id = $row['ID']; echo "<td><a href='/view_message.php/?view_message=$id'>View</a></td>"; if ($row['message_status'] == 'read') { $img ='green.jpg'; } else { $img ='red.jpg'; } echo '<td><img src="assets/' . $img . '"/></td>'; echo "<td>" .$bold . $message_status = $row['message_status'] . "</td>"; echo "<td>" .$bold. $row['date_sent'] . "</td>"; echo "<td>" .$bold. $row['contact_name'] . "</td>"; echo "<td>" .$bold. $row['subject'] . "</td>"; echo "</tr>"; } Quote Link to comment https://forums.phpfreaks.com/topic/223721-variable-in-database-result/#findComment-1156396 Share on other sites More sharing options...
Psycho Posted January 7, 2011 Share Posted January 7, 2011 I would also add that having two statuses with the values of "read" and "unread" is not ideal. Unless you plan to add additional statuses I would suggest the database column be called "read" and you should store a boolean value (i.e. true/false). Anyway, building upon dropkick_pdx's suggestioin here is what I would propose. 1. Add CSS code to your page or to an external style sheet to create two classes "read" and "unread". 2. Name the images "read.jpg" and "unread.jpg" 3. Add the following logic to the top of your script (ionclude the db query of course): $messagesHTML = ''; while ($row = mysql_fetch_assoc($result)) { $messagesHTML .= " <tr class=\"{$row['message_status']}\">\n"; $messagesHTML .= " <td><img src=\"assets/{$row['message_status']}.jpg\" /></td>\n"; $messagesHTML .= " <td>{$row['message_status']}</td>\n"; $messagesHTML .= " <td>{$row['date_sent']}</td>\n"; $messagesHTML .= " <td>{$row['contact_name']}</td>\n"; $messagesHTML .= " <td>{$row['subject']}</td>\n"; $messagesHTML .= " <tr>\n"; } 4. Then in the body of the HTML code do this <table border="1"> <tr width="200"> <th>View</th> </tr> <?php echo $messagesHTML; ?> </table> Quote Link to comment https://forums.phpfreaks.com/topic/223721-variable-in-database-result/#findComment-1156402 Share on other sites More sharing options...
AJLX Posted January 7, 2011 Author Share Posted January 7, 2011 Hello Guys, Many thanks for taking the time to reply. This has worked perfectly! Once again many thanks! Regards, AJLX Quote Link to comment https://forums.phpfreaks.com/topic/223721-variable-in-database-result/#findComment-1156460 Share on other sites More sharing options...
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