Variables not working right....

[Call-911]

Hello All,

 

In below script, I'm using another script called "SimpleImage.php" to upload and resize photos for a news site. The problem comes with renaming the photos. I need to name the photo based off of the story id. I have everything right to get the story id, but saving it as the variable is what's confusing me.

 

Here's what I have:

 

<?php include ("newsconnection.php");?>
<?php
$picturename = $_POST['newstoryid'];

      include('SimpleImage.php');
      $image = new SimpleImage();
      $image->load($_FILES['uploaded_image']['tmp_name']);
      $image->resizeToWidth(300);
      $image->save('$picturename');

?>

 

It's the $image->save('$picturename'); line that's messing me up. Any help would be great!!

[beegro]

You're using single quotes around a PHP variable

 

$image->save('$picturename');

That treats the string literally instead of as the $picturename value.

 

Try

 

$image->save($picturename);

[Call-911]

Would saving it in a directory and as a .jpg be:

 

$image->save('uploadedphotos/'$picturename'.jpg');

 

or should I include that in the variable?

 

$picturename = 'uploadedphotos/'$_POST['newstoryid']'.jpg';

[chronister]

$image->save('uploadedphotos/'.$picturename.'.jpg');

 

You have to have the additional periods to properly concatenate the string.

[Call-911]

Perfect! Thanks guys!