tryingtolearn Posted January 15, 2011 Share Posted January 15, 2011 Cant seem to figure this one out for a chained script. In the code below I need to take the value of $drop_var from function drop_1() and send it to function drop_2() So I can add it to the Where clause to limit the results of the third box a little more. But I cannot get the value to pass to the function. Any help appreciated. func.php <?php //************************************** // Page load dropdown results // //************************************** function getTierOne() { $result = mysql_query("SELECT DISTINCT branch FROM rank") or die(mysql_error()); while($tier = mysql_fetch_array( $result )) { echo '<option value="'.$tier['branch'].'">'.$tier['branch'].'</option>'; } } //************************************** // First selection results // //************************************** if($_GET['func'] == "drop_1" && isset($_GET['func'])) { drop_1($_GET['drop_var']); } function drop_1($drop_var) { include_once('db.php'); $result = mysql_query("SELECT DISTINCT type FROM rank WHERE branch='$drop_var'") or die(mysql_error()); echo '<select name="drop_2" id="drop_2"> <option value=" " disabled="disabled" selected="selected">Choose one</option>'; while($drop_2 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_2['type'].'">'.$drop_2['type'].'</option>'; } echo '</select>'; echo "<script type=\"text/javascript\"> $('#wait_2').hide(); $('#drop_2').change(function(){ $('#wait_2').show(); $('#result_2').hide(); $.get(\"func.php\", { func: \"drop_2\", drop_var2: $('#drop_2').val() }, function(response){ $('#result_2').fadeOut(); setTimeout(\"finishAjax_tier_three('result_2', '\"+escape(response)+\"')\", 400); }); return false; }); </script>"; } //************************************** // Second selection results // //************************************** if($_GET['func'] == "drop_2" && isset($_GET['func'])) { drop_2($_GET['drop_var2']); } function drop_2($drop_var2) { echo "<br>($drop_var)<br>"; include_once('db.php'); $result = mysql_query("SELECT * FROM rank WHERE type='$drop_var2'") or die(mysql_error()); echo '<select name="drop_3" id="drop_3"> <option value=" " disabled="disabled" selected="selected">Choose one</option>'; while($drop_3 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_3['grade'].'">'.$drop_3['grade'].'</option>'; } echo '</select>'; echo '<input type="submit" name="submit" value="Submit" />'; } ?> index.php <?php include('db.php'); include('func.php'); ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Chained Select Boxes using PHP, MySQL and jQuery</title> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#wait_1').hide(); $('#drop_1').change(function(){ $('#wait_1').show(); $('#result_1').hide(); $.get("func.php", { func: "drop_1", drop_var: $('#drop_1').val() }, function(response){ $('#result_1').fadeOut(); setTimeout("finishAjax('result_1', '"+escape(response)+"')", 400); }); return false; }); }); function finishAjax(id, response) { $('#wait_1').hide(); $('#'+id).html(unescape(response)); $('#'+id).fadeIn(); } function finishAjax_tier_three(id, response) { $('#wait_2').hide(); $('#'+id).html(unescape(response)); $('#'+id).fadeIn(); } </script> </head> <body> <p> <form action="" method="post"> <select name="drop_1" id="drop_1"> <option value="" selected="selected" disabled="disabled">Select a Category</option> <?php getTierOne(); ?> </select> <span id="wait_1" style="display: none;"> <img alt="Please Wait" src="ajax-loader.gif"/> </span> <span id="result_1" style="display: none;"></span> <span id="wait_2" style="display: none;"> <img alt="Please Wait" src="ajax-loader.gif"/> </span> <span id="result_2" style="display: none;"></span> </form> </p> <p> <?php if(isset($_POST['submit'])){ $drop = $_POST['drop_1']; $drop_2 = $_POST['drop_2']; $drop_3 = $_POST['drop_3']; echo "You selected a "; echo $drop_3." ".$drop." ".$drop_2; } ?> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/224551-pass-a-var-from-1-function-to-another/ Share on other sites More sharing options...
marcus Posted January 16, 2011 Share Posted January 16, 2011 Hope this makes some sense. <?php function drop_1($drop_var){ /** * all code here before starting to echo **/ $var = 'anything you are going to echo'; $var .= 'add some more stuff to the variable!'; $var .= 'one more add is fun!'; return $var; # instead of using echo return the variable, so then you could do something like (look below) } echo drop_1($_GET['drop_var']); # this will echo $var function drop_2($drop_var){ /** * wherever you want to use the output from drop_1 you would just do **/ echo drop_1($drop_var); # then whatever you want to echo afterward } ?> Quote Link to comment https://forums.phpfreaks.com/topic/224551-pass-a-var-from-1-function-to-another/#findComment-1160014 Share on other sites More sharing options...
tryingtolearn Posted January 16, 2011 Author Share Posted January 16, 2011 Well it sort of makes sense but the problem is when I try to implement it it echos another drop box not a value So Im not too sure whats going on. Unless Im missing something that you meant. I read about the functions variables scope etc... so its making sense but not working. <?php //************************************** // Page load dropdown results // //************************************** function getTierOne() { $result = mysql_query("SELECT DISTINCT branch FROM rank") or die(mysql_error()); while($tier = mysql_fetch_array( $result )) { echo '<option value="'.$tier['branch'].'">'.$tier['branch'].'</option>'; } } //************************************** // First selection results // //************************************** if($_GET['func'] == "drop_1" && isset($_GET['func'])) { drop_1($_GET['drop_var']); } function drop_1($drop_var) { include_once('db.php'); $result = mysql_query("SELECT DISTINCT type FROM rank WHERE branch='$drop_var'") or die(mysql_error()); $branch=$drop_var; echo '<select name="drop_2" id="drop_2"> <option value=" " disabled="disabled" selected="selected">Choose one</option>'; while($drop_2 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_2['type'].'">'.$drop_2['type'].'</option>'; } echo '</select>'; echo "<script type=\"text/javascript\"> $('#wait_2').hide(); $('#drop_2').change(function(){ $('#wait_2').show(); $('#result_2').hide(); $.get(\"func.php\", { func: \"drop_2\", drop_var: $('#drop_2').val() }, function(response){ $('#result_2').fadeOut(); setTimeout(\"finishAjax_tier_three('result_2', '\"+escape(response)+\"')\", 400); }); return false; }); </script>"; return $branch; } //************************************** // Second selection results // //************************************** if($_GET['func'] == "drop_2" && isset($_GET['func'])) { drop_2($_GET['drop_var']); } function drop_2($drop_var) { include_once('db.php'); $result = mysql_query("SELECT * FROM rank WHERE type='$drop_var'") or die(mysql_error()); echo drop_1($drop_var); echo '<select name="drop_3" id="drop_3"> <option value=" " disabled="disabled" selected="selected">Choose one</option>'; while($drop_3 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_3['grade'].'">'.$drop_3['grade'].'</option>'; } echo '</select> '; echo '<input type="submit" name="submit" value="Submit" />'; } ?> Quote Link to comment https://forums.phpfreaks.com/topic/224551-pass-a-var-from-1-function-to-another/#findComment-1160037 Share on other sites More sharing options...
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