Dynamic variable array ?!

[chrisran]

Hi !

 

I'd like to count all occurences in "$thiscodestring" into a "dynamic?" array and print it out after the end of the loop, how do I assign the variablenames dynamically ?

 

$query = "SELECT codes, status FROM table";

 

while ($row = mysql_fetch_assoc($result)) {

  $thiscodestring = $row[codes];  // looks like "a1 c2 d3 10 15 1 a1 a1";

  $singlecodes = explode(" ", $thiscodestring);

    foreach($singlecodes as $thiscode) {

      $$thiscode[count] = $$thiscode[count] + 1;

    }

}

 

After all Mysql-Stuff is done I'd like to print out the counted codes, for example the code "a1" was found 100 times in all querys then $$a1[count] should be 100, c2 was found 15 times, then $$c2[count] should be 15 and so on.

 

Question:

How do I tell php to assign a "dynamic" variable with the name of the found string which was exploded (in this example a1, c2, d3... ) before ?!

 

$$ does not seem to work.

 

And how can I then print_r() the value if I dont know the name ?

 

Thanks !

[Roman Fedorov]

Hi chrisran,

you should just use an array, using $thiscode as the key, and incrementin the value:

$query = "SELECT codes, status FROM table";

$codes = Array();
while ($row = mysql_fetch_assoc($result)) {
  $thiscodestring = $row[codes];  // looks like "a1 c2 d3 10 15 1 a1 a1";
  $singlecodes = explode(" ", $thiscodestring);
    foreach($singlecodes as $thiscode) {
      $codes[$thiscode]++;
    }
  print_r($codes);
}

[parino_esquilado]

To create a dynamic variable you need to wrap the second dollar with {} curly braces:

 

<?php
$variableName = "a1";
${$variableName} = 100;
?>

 

which would create a an $a1 variable with the value of 100 ($a1 = 100).