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how: find a line replace it and return just that change line?


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what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video

after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

 

to do this i know that i need something like this to get the URL of the video

http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)

but how to only return just the URL is something idk how to do

 

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

 

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL

 

 

this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

 

http://www.phpf1.com/tutorial/get-current-page-url.html

 

that link might help you, you need to use the $_SERVER to get the content you need.

 

that not the type of URL im trying to get :D lol

 

here is a youtube embed

<object width="640" height="385"><param name="movie" value="http://www.youtube.com/v/cr19U8TVJtw?fs=1&hl=en_US&rel=0"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/cr19U8TVJtw?fs=1&hl=en_US&rel=0" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="640" height="385"></embed></object>

 

what im trying to grab is

http://www.youtube.com/v/cr19U8TVJtw?fs=1&hl=en_US&rel=0

but i dont want anything before this and dont want the "?" and all that other things pass that

 

so what im asking is how would i grab just

http://www.youtube.com/v/cr19U8TVJtw

 

 

I made a function to do that, or can use anything would want from in it if looks at the values and remove/include the parts like you want them

 

see the post here, also look at the one below it

http://www.phpfreaks.com/forums/php-coding-help/getting-the-path/msg1506898/#msg1506898

 

php has a built in parse_url function

http://www.php.net/manual/en/function.parse-url.php

<?php
function removeQuery($insert_link){
$query_parse_url = parse_url($insert_link, PHP_URL_QUERY);
$new_link = str_replace("?$query_parse_url",'',$insert_link);
return $new_link;
}
?>
<?php
//usage
$url = removeQuery("http://www.youtube.com/v/cr19U8TVJtw?fs=1&hl=en_US&rel=0");
echo $url;
?>

ty you QuickOldCar and Sorry for wasting your time I believe i may have found a better way for me to do it it may not be as cool as your coding :D but it gets the job done lol

plus was having a hard time trying to find out how your worked :D

if there was a way to rank you up i would

 

Im not to sure how or why this code works but it does lol

i give it a youtube embed and it gives me back http://i2.ytimg.com/vi/cr19U8TVJtw/default.jpg what is what i wanted

if (preg_match("#http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+).+?#i", "$video_url")) {
$pre_regex = '#<object[^>]+>.+?'.
'http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+).+?</object>#s';
$pre_replace = 'http://i2.ytimg.com/vi/\1/default.jpg';
$try9=preg_replace($pre_regex, $pre_replace, $video_url);
}

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