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Hi all,

 

Can anyone tell me why my jquery validate will not run when I use my image swap script? I am relatively new to jquery and javascript in general and I don't understand what the issue is, if I remove my links with the onmouseover and onmouseout functions then the validator works fine, however if I leave them in then the form just executes.

 

My code:

<script type="text/javascript" src="scripts/pageload.js"></script>
<script type="text/javascript" src="scripts/formhelper.js"></script>
<script type="text/javascript" src="scripts/jquery-1.4.2.js"></script>
<script type="text/javascript" src="scripts/jquery.validate.pack.js"></script>

<script type="text/javascript">

  $(document).ready(function(){
    $("#purchase").validate();
  });
  function swapImages(that) {
  that.src =  (that.src.indexOf('buttonselected')>-1) ? ("images/"+that.id+"button.gif") : ("images/"+that.id+"buttonselected.gif");
}

  </script>

</head>

<body>
<div id="main">
<div id="links">
	<a href="index.php"><img src="images/homebutton.gif" alt="Home Button" class="buttons" id="home" onmouseover="swapImages(this)" onmouseout="swapImages(this)" /></a>
	<a href="packages.php"><img src="images/packagebutton.gif" alt="Packages Button" class="buttons" id="package" onmouseover="swapImages(this)" onmouseout="swapImages(this)" /></a>
<a href="purchase.php"><img src="images/purchasebutton.gif" alt="Purchase Button" class="buttons" id="purchase" onmouseover="swapImages(this)" onmouseout="swapImages(this)" /></a>
	<img src="images/contactbutton.gif" alt="Contact Button" class="buttons" id="contact" onmouseover="swapImages(this)" onmouseout="swapImages(this)" />
        <img src="images/clientbutton.gif" alt="Client Button" class="buttons" id="client" onmouseover="swapImages(this)" onmouseout="swapImages(this)" />

 

Many Thanks

 

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