Guest Posted February 5, 2011 Share Posted February 5, 2011 I have a function that prompts a user for some text and a hexadecimal color: function bg_color(thisField) { var text = prompt('Enter text:', ''); var color = prompt('Enter background color:', '#'); while (!color.match(/\#{1}[A-Za-z0-9]{6}/)) { alert('Must be a hexadecimal color!'); var color = prompt('Enter background color:', '#'); } if (text != null && color != null) { document.thisForm.elements[thisField].value += "<bg color=\"" + color + "\">" + text + "</bg>"; } } The problem it is seems to completely ignore the numbers in curly brackets. I can put any number of #'s in front of the number of any number of digits after the #'s and it will be just fine with it. I want the function to continue asking for a hexadecimal color until it gets one # in front and 6 digits afterwards. Anyone know how to do this? Quote Link to comment Share on other sites More sharing options...
.josh Posted February 6, 2011 Share Posted February 6, 2011 while (!color.match(/^#[A-Fa-f0-9]{6}$/)) { - you don't need to escape # - you don't need to do #{1} as it is superfluous - hexadecimal numbers only contain letters a-f not a-z - main thing you were missing was start and end of string anchors (^...$) which tells the regex engine that it must start with the # followed by 6 a-f0-9 and then nothing else. Quote Link to comment Share on other sites More sharing options...
Guest Posted February 7, 2011 Share Posted February 7, 2011 Awesome! Thanks, Crayon! Quote Link to comment Share on other sites More sharing options...
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