spacepoet Posted February 8, 2011 Share Posted February 8, 2011 Hello: I have a SELECT dropdown menu that works like this: <?php $states_arr = array('AL'=>"Alabama",'AK'=>"Alaska",'AZ'=>"Arizona",'AR'=>"Arkansas",'CA'=>"California",'CO'=>"Colorado",'CT'=>"Connecticut",'DE'=>"Delaware",'DC'=>"District Of Columbia",'FL'=>"Florida",'GA'=>"Georgia",'HI'=>"Hawaii",'ID'=>"Idaho",'IL'=>"Illinois", 'IN'=>"Indiana", 'IA'=>"Iowa", 'KS'=>"Kansas",'KY'=>"Kentucky",'LA'=>"Louisiana",'ME'=>"Maine",'MD'=>"Maryland", 'MA'=>"Massachusetts",'MI'=>"Michigan",'MN'=>"Minnesota",'MS'=>"Mississippi",'MO'=>"Missouri",'MT'=>"Montana",'NE'=>"Nebraska",'NV'=>"Nevada",'NH'=>"New Hampshire",'NJ'=>"New Jersey",'NM'=>"New Mexico",'NY'=>"New York",'NC'=>"North Carolina",'ND'=>"North Dakota",'OH'=>"Ohio",'OK'=>"Oklahoma", 'OR'=>"Oregon",'PA'=>"Pennsylvania",'RI'=>"Rhode Island",'SC'=>"South Carolina",'SD'=>"South Dakota",'TN'=>"Tennessee",'TX'=>"Texas",'UT'=>"Utah",'VT'=>"Vermont",'VA'=>"Virginia",'WA'=>"Washington",'WV'=>"West Virginia",'WI'=>"Wisconsin",'WY'=>"Wyoming"); function showOptionsDrop($array){ $string = ''; foreach($array as $k => $v){ $string .= '<option value="'.$k.'"'.$s.'>'.$v.'</option>'."\n"; } return $string; } ?> <form> <select name="states"> <option value="0">Choose a state</option> <?php echo showOptionsDrop($states_arr); ?> </select> </form> I would like to show all the towns/zipcodes for each individual state with an "onchange" from the SELECT menu. The table is called "zip_codes" and the City/Zip Codes are called "city" and "zip" What I would like to do is display them as links, so a user can click into each town and either create a new entry (a restaurant) or update an existing entry. What would be the best approach for this? I appreciate the help. Link to comment https://forums.phpfreaks.com/topic/227017-showing-data-with-onchange-from-slect-menu-whats-the-best-way/ Share on other sites More sharing options...
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