quick question:)

[Toy]

hey! I have a site where I want to use multiple issets at the same time, like if I have four buttons and four issets:

if(isset($_POST['one']))
{
echo '<div class="example_box">one</div>';
}

if(isset($_POST['two']))
{
echo '<div class="example_box">two</div>';
}

if(isset($_POST['three']))
{
echo '<div class="example_box">three</div>';
}

if(isset($_POST['four']))
{
echo '<div class="example_box">four</div>';
}

 

but for some reason it seems like only one isset can be activate at a time, is there any way to work this out or something :s?

 

I've tried some variants of elseif stuff and such, but yeah, I'm pretty new at this stuff

[sasa]

you can't pres more then one button in time

 

try some other type of input tags

[Toy]

oh, that's sad

 

does anyone know any other ways of doing this if not using issets? it would be helpfull:)

 

edit:oh, I didn't read your post properly, you mean like using text links or things like that?okay,thanks! would still need some help on how!

[Altrozero]

Hidden input fields could be used instead if you really wanted.

 

you could go in your HTML

 

<form method="post" action="">

<input type="hidden" value="value1" name="one" />

<input type="hidden" value="value2" name="two" />

<input type="hidden" value="value3" name="three" />

<input type="hidden" value="value4" name="four" /><input type="submit" value="submit" />

</form>

[Toy]

Hidden input fields could be used instead if you really wanted.

 

you could go in your HTML

 

<form method="post" action="">

<input type="hidden" value="value1" name="one" />

<input type="hidden" value="value2" name="two" />

<input type="hidden" value="value3" name="three" />

<input type="hidden" value="value4" name="four" /><input type="submit" value="submit" />

</form>

 

wouldn't that just show all of the boxes :S?

[Altrozero]

I thought that is what you wanted? You haven't really explained what the output should look like? Depending on the users input.

[sasa]

use checkbox

[swharrell]

I assume you are wanting to display a specific div based on the users input. Try:

<form name="form" action="<? echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="text" value="" name="input">
<input type="submit" name="submit" value="submit">
</form>
<?php
$num = $_POST['input'];

switch ($num){
case 'one':
	echo '<div class="example_box">one</div>';
	break;
case 'two':
	echo '<div class="example_box">two</div>';
	break;
case 'three':
	echo '<div class="example_box">three</div>';
	break;
case 'four':
	echo '<div class="example_box">four</div>';
	break;
default:
	echo 'Default';
	break;
}								
?>

 

[Toy]

@sasa, I'd rather not as it would look totally wrong

 

@swharrell, actually I'm not trying to do it on user input

 

Look, there's simply four buttons, when I press button one, div 1 is going to appear, if I then click button three, div 3 is going to appear but div 1 should still be visible, get my drift?

 

Is there any alternative to issets or whatever, because I'd love to not have to use checkboxes

[jcbones]

Use Javascript

[Altrozero]

Use javascript or save previous input to either a database or a users session/cookie. There are a few tutorials around to save data.