dean7 Posted February 28, 2011 Share Posted February 28, 2011 Hi all, I'm currently adding something to my website which makes the user input some information before they enter the site, but I'm getting errors saying.. Notice: Undefined index: realname in /home/a5908246/public_html/next.php on line 24 Notice: Undefined index: gamer in /home/a5908246/public_html/next.php on line 48 But with them errors its not showing the actual form where you post the info into. <?php session_start(); include ("includes/config.php"); include ("includes/functions.php"); logincheck(); ini_set ('display_errors', 1); error_reporting (E_ALL); $username = $_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username='$username'") or die (mysql_error()); $got = mysql_fetch_object($get); ?> <html> <head> <title>Please Update..</title> </head> <body> <form action='' method='POST' name='everything'> <?php if ($got->realname == ''){ if ($_POST['realname']){ // Line 24 $input = $_POST['nameinput']; ?> <table width='50%' border='1' class='tableborder2' cellspacing='1' align='center'> <tr> <td class='e_header' align='center'>Error!</td> </tr> <tr> <td class='omg' align='center'>Please Enter your Real Name.</td> </tr> <tr> <td align='center'><input type='text' name='nameinput' class='textinput'></td> </tr> <tr> <td align='center'><input type='button' name='realname' class='button' Value='Update Name!'></td> </tr> </table> <br /> <?php mysql_query ("UPDATE users SET realname='$input' WHERE username='$username'") or die (mysql_error()); }} ?> <?php if ($got->gamertag == ''){ if ($_POST['gamer']){ // Line 48 $inputgamer = $_POST['gamertag']; ?> <table width='50%' border='1' class='tableborder2' cellspacing='1' align='center'> <tr> <td class='e_header' align='center'>Error!</td> </tr> <tr> <td class='omg' align='center'>Please Enter your Gamertag.</td> </tr> <tr> <td align='center'><input type='text' name='gamertag' class='textinput'></td> </tr> <tr> <td align='center'><input type='button' name='gamer' class='button' Value='Update Gamertag!'></td> </tr> </table> <?php mysql_query ("UPDATE users SET gamertag='$inputgamer' WHERE username='$username'") or die (mysql_error()); }} if ($got->realname != '' || $got->gamertag != ''){ // Display, welcome $realname, redirecting you to main site now... (2 seconds waiting) ?> <table width='50%' border='1' class='tableborder2' cellspacing='1' align='center'> <tr> <td class='header' align='center'>Welcome!</td> </tr> <tr> <td class='omg' align='center'>Welcome!</td> </tr> <tr> <td align='center'>You will be redirected to the main site in 2 seconds!<meta http-equiv="refresh" content="2;url=http://******.com/index2.php"></td> </tr> </table> </form> <?php } ?> Thanks for any help/advice given Link to comment https://forums.phpfreaks.com/topic/229121-undefined-indexs/ Share on other sites More sharing options...
flolam Posted February 28, 2011 Share Posted February 28, 2011 are you sure that $_POST["realname"] is not empty? Link to comment https://forums.phpfreaks.com/topic/229121-undefined-indexs/#findComment-1180729 Share on other sites More sharing options...
dean7 Posted February 28, 2011 Author Share Posted February 28, 2011 are you sure that $_POST["realname"] is not empty? Its only emtpy untill someone posts in the box the information to Update. Link to comment https://forums.phpfreaks.com/topic/229121-undefined-indexs/#findComment-1180732 Share on other sites More sharing options...
flolam Posted February 28, 2011 Share Posted February 28, 2011 so you are showing the form to set $_POST["realname"] only if this variable already is set? to get rid of the notice, I think you should use if (isset($_POST['realname'])) Link to comment https://forums.phpfreaks.com/topic/229121-undefined-indexs/#findComment-1180734 Share on other sites More sharing options...
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