Jump to content

Code not showing output


mdmartiny

Recommended Posts

This is the code that I am using to make a page that is kind of like an administration area for a CMS system. When the page is loading all I get is a blank page.

 

When I remove all of the back code before the HTML code is sent. The page shows up fine. I have looked over and over the code trying to see if I missed a colon or something and I see nothing.

 

I hope that this explains everything well enough and I would appreciate any help.

 

<?php
$today = date("l, F j, Y");

$host ='';
$username = '';
$dbname ='';
$dbpassword = '';
$table = '';
$table2 = '';

$connection = mysql_connect($host, $username, $dbpassword) or die (mysql_error());
$db = mysql_select_db ($dbname, $connection) or die (mysql_error());

$sql = "SELECT * FROM $table WHERE username = '$_POST[username]' AND password = password('$_POST[password]')";	
$result = mysql_query($sql, $connection) or die(mysql_error());
$num = mysql_num_rows($result);

while ($row = mysql_fetch_array($result)) {
$f_name = $row['f_name'];
$l_name = $row['l_name'];
$username = $row['username'];
}


if ($num != 0) {
$_SESSION[auth] = "yes";
$msg = "Welcome $f_name ";
} //else {
//header("Location: index.php");
//exit;
//}

$get_count = "SELECT count(id) FROM $table2";
$get_count_res = mysql_query($get_count, $connection) or die (mysql_error());
$count = mysql_result($get_count_res, 0, "count(id)") or die (mysql_error());


?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="css/reset.css" media="screen" />
<link rel="stylesheet" type="text/css" href="css/admin.css" media="screen"  />
<title>Administration Area</title>
</head>
<body>
<div id="wrapper">
   <?php include('includes/header.php'); ?>
   <div id="content">
      <div class="message"><?php echo "$msg"; ?> <a href="logout.php">Logout</a><span style="float:right; "><?php echo "$today"; ?></span></div>
      <div class="admin"> <span class="top">Administration</span>
         <ul>
            <li><A href="show_add.php">Add a Ad</A></li>
            <li><a href="pick_modify.php">Modify a Add</a></li>
            <li>Delete Ad</li>
            <li><a href="user/index.php">Add a User</a></li>
            <li><a href="user/pick_user.php">Delete a User</a></li>
            <li><a href="#">View Database Records</a></li>
            <li><a href="php_info.php">PHP info</a></li>
            <li><a href="make_backup.php">Backup Database</a> </li>
            <li><a href="https://p3nlmysqladm001.secureserver.net/nl50/529/index.php?lang=en-utf-8&token=db052d2ddafce3f6ba841cfe0a6c224a">View Database</a> </li>
         </ul>
      </div>
      <div class="misc"><span class="top">miscellaneous</span>Classified
         Ads online <?php echo "$count"; ?></div>
   </div>
   <!--End #content-->
   <?php include('includes/footer.php'); ?>
</div>
<!-- End #wrapper -->
</body>
</html>

Link to comment
https://forums.phpfreaks.com/topic/229418-code-not-showing-output/
Share on other sites

Are you developing and debugging your code on a system with error_reporting set to E_ALL and display_errors set to ON in your master php.ini so that all the errors php detects will be reported and displayed? You will save a TON of time.

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.