andrej13 Posted March 10, 2011 Share Posted March 10, 2011 I need this form to be sent to a mail after you press the button and to see the content that is sent , what is the easiest way to do this? http://fhcs.be/ <?php // Include MySQL class require_once('inc/mysql.class.php'); // Include database connection require_once('inc/global.inc.php'); // Include functions session_start(); $dranken=array(); $DrinkResult=mysql_query("SELECT name,price FROM products" )or die(mysql_error()); while($DrinkRow=mysql_fetch_assoc($DrinkResult)) { $dranken[]=$DrinkRow; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head></head> <body> <?php if (!isset($_POST['submit'])) { ?> <form method="post" action="mail.php"> <input type="submit" value="Toon Output" name="submit"/> <?php echo "<table>"; foreach ($dranken as $DrinkRow) { $optionlist = "<select name='{$DrinkRow['name']}_aantal'>"; for($i=0;$i<10;++$i) { $optionlist .= "<option value='$i'>$i</option>"; } $optionlist .= "</select>"; echo "<tr><td>". $DrinkRow['name']."</td><td>".$DrinkRow['price']."</td>"; echo "<td>$optionlist</td></tr>"; } echo "</table>"; ?> </form> <?php } else { echo "<table>"; $totaalPrijs = 0; foreach ($dranken as $DrinkRow) { $aantal = $_POST[ $DrinkRow['name'] . "_aantal"]; if ($aantal > 0) { $prijsperDrank = $aantal * $DrinkRow['price']; echo $DrinkRow['name'] . " : " . $aantal . " Prijs: " . $prijsperDrank . "</br>"; $totaalPrijs=$totaalPrijs + $prijsperDrank; } } if($totaalPrijs>0) { echo " totaal: " .$totaalPrijs; } echo "</table>"; } ?> </body> </html> Link to comment https://forums.phpfreaks.com/topic/230251-send-form-to-mail/ Share on other sites More sharing options...
HuggieBear Posted March 11, 2011 Share Posted March 11, 2011 Take a look at mail() Link to comment https://forums.phpfreaks.com/topic/230251-send-form-to-mail/#findComment-1186090 Share on other sites More sharing options...
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