anevins Posted March 20, 2011 Share Posted March 20, 2011 What I expect: - The function to loop output all of the rows which match the search results. The problems: - Only 1 row is matched. - Notice: Undefined index: id in G:\xampp\htdocs\xampp\dsa\search_func.php on line 57 - The image is not showing Line 57: $id = $_REQUEST['id']; Entire Code: <?php /* return the details of an employee parameter empno - employee number eg empHTML.php?empno=7521 This is very basic e.g no error checking */ function search($dbc, $id) { if (isset($_GET['terms']) && ($_GET['terms'] != 'Search...') ) { $terms = $_GET['terms']; $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) or die *('Error connecting to MySQL server'); $query = "SELECT * FROM stick, location, identification WHERE make LIKE '%$terms%' AND stick.sid = location.lid AND identification.stickID = stick.sid AND identification.stickID = $id"; $result=mysqli_query($dbc,$query); $num_rows = mysqli_num_rows($result); $output = Array(); $image = mysqli_fetch_object($result); if ($num_rows > 0){ if($result=mysqli_query($dbc,$query)){ $output[] = '<ul>'; $output[] = '<li> Type: '.$image->make .'<br />Size: '.$image->size .$image->type .'<br />Colour: '.$image->colour . '<br /> Street Missing in: ' .$image->street.'<br />Town missing in: '.$image->town .'<br />City missing in: '.$image->city.'</li>'; $output[] = '</ul>'; } return join('',$output); } else { echo "<h3>Sorry,</h3>"; echo "<p>your search: "" .$terms. "" returned zero results</p>"; } } else { // Tell them to use the search form. echo '<p class="error">Please use the search form at the top of the window to search this site.</p>'; } } // connect $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); // get the id from the URL $id = $_REQUEST['id']; print search($dbc, $id); print "<img src='getPhoto.php?id=$id'/>"; // close the database mysqli_close($dbc); Link to comment https://forums.phpfreaks.com/topic/231180-new-search-results/ Share on other sites More sharing options...
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