herghost Posted April 23, 2011 Share Posted April 23, 2011 First, apologies if this is in the wrong section, basically I am not sure what language my problem lies! Here is the general over view. I have a jquery script that automatically selects a group of sub categorys and pus them in a select list depending on the input of a first select list, so you can choose you main cat and then the sub cats for this cat appear in the next list, this all works fine, the basic code is below: <script type="text/javascript"> $(document).ready(function() { $('#wait_1').hide(); $('#drop_1').change(function(){ $('#wait_1').show(); $('#result_1').hide(); $.get("scripts/func.php", { func: "drop_1", drop_var: $('#drop_1').val() }, function(response){ $('#result_1').fadeOut(); setTimeout("finishAjax('result_1', '"+escape(response)+"')", 400); }); return false; }); }); function finishAjax(id, response) { $('#wait_1').hide(); $('#'+id).html(unescape(response)); $('#'+id).fadeIn(); } </script> <form action='do.php' method='post'> <select name="drop_1" id="drop_1"> <option value="" selected="selected" disabled="disabled">Select a Category</option> <?php getTierOne(); ?> </select> <span id="wait_1" style="display: none;"> <img alt="Please Wait" src="images/ajax-loader.gif"/> </span> <span id="result_1" style="display: none;"></span> This calls scripts/func.php <?php //************************************** // Page load dropdown results // //************************************** function getTierOne() { $result = mysql_query("SELECT * FROM blog_cats") or die(mysql_error()); while($tier = mysql_fetch_array( $result )) { echo '<option value="'.$tier['cat_id'].'">'.$tier['cat_name'].'</option>'; } } //************************************** // First selection results // //************************************** if($_GET['func'] == "drop_1" && isset($_GET['func'])) { drop_1($_GET['drop_var']); } function drop_1($drop_var) { include_once('../connect.php'); $result = mysql_query("SELECT * FROM blog_subs WHERE cat_id='$drop_var'") or die(mysql_error()); echo '<select name="tier_two" id="tier_two"> <option value=" " disabled="disabled" selected="selected">Select Sub Catergory</option>'; while($drop_2 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_2['sub_id'].'">'.$drop_2['sub_name'].'</option>'; } echo '</select> '; } ?> The problem I am having is getting the second select (tier_two) to pass to my form processing page. I just get an undefined variable error Many Thanks Quote Link to comment https://forums.phpfreaks.com/topic/234506-problem-with-parsing-variable-to-form/ Share on other sites More sharing options...
herghost Posted April 25, 2011 Author Share Posted April 25, 2011 Anyone have any ideas about this? is there a way of passing the value from func.php back to the main form? Quote Link to comment https://forums.phpfreaks.com/topic/234506-problem-with-parsing-variable-to-form/#findComment-1205945 Share on other sites More sharing options...
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