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need help to fix my php script


tiweb

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error Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/nrkgamin/public_html/perp/gameserver/fetch_users5.php on line 7

<?php
mysql_connect("xxxxxxx", "xxxxxxxx", "xxxxxxx");
mysql_select_db("phpbb");

$query = mysql_query("SELECT phpbb_profile_fields_data.pf_steamid, phpbb_users.user_rank FROM user, phpbb_profile_fields_data WHERE (phpbb_users.user_rank='16' OR phpbb_users.user_rank='10' OR phpbb_users.user_rank='9' OR phpbb_users.user_rank='14' OR phpbb_users.user_rank='11' OR phpbb_users.user_rank='15' OR phpbb_users.user_rank='13' OR phpbb_users.user_rank='12' OR phpbb_users.user_rank='44' OR phpbb_users.user_rank='47') AND phpbb_users.user_id=phpbb_profile_fields_data.user_id");

while ($row = mysql_fetch_assoc($query)){
	if ($row['pf_steamid'] != "" && $row['user_rank'] != ""){
		echo $row['pf_steamid'] . "\t" . $row['user_rank'] . "\n";
	}
}

?>

srr for my bad english

 

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try this to help determine the error

this is wrong: while ($row = mysql_fetch_assoc($query)){

should be: $result=mysql_query($query) or $debug_message.=mysql_error()."<br>";

while ($row = mysql_fetch_assoc($result)){

 

<?php
mysql_connect("xxxxxxx", "xxxxxxxx", "xxxxxxx");
mysql_select_db("phpbb");
$debug_message="START DEBUG<br/>";

$query = mysql_query("SELECT phpbb_profile_fields_data.pf_steamid, phpbb_users.user_rank FROM user, phpbb_profile_fields_data WHERE (phpbb_users.user_rank='16' OR phpbb_users.user_rank='10' OR phpbb_users.user_rank='9' OR phpbb_users.user_rank='14' OR phpbb_users.user_rank='11' OR phpbb_users.user_rank='15' OR phpbb_users.user_rank='13' OR phpbb_users.user_rank='12' OR phpbb_users.user_rank='44' OR phpbb_users.user_rank='47') AND phpbb_users.user_id=phpbb_profile_fields_data.user_id");
$result=mysql_query($query) or $debug_message.=mysql_error()."<br>";
while ($row = mysql_fetch_assoc($result)){
	if ($row['pf_steamid'] != "" && $row['user_rank'] != ""){
		echo $row['pf_steamid'] . "\t" . $row['user_rank'] . "\n";
	}
}
debug_message.="END DEBUG MESSAGE<br/>";
echo $debug_message;
?>

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