debbie-g85 Posted April 30, 2011 Share Posted April 30, 2011 This might be a very easy problem to solve. I am literally brand new to php. I am trying to create a simple site that will load content depending on what page 'id' is in the URL and if it doesn't exist to show a page for that scenario. eg index.php?id=1 will show the page 1.php It works fine apart from showing an error when there is no id at all, eg www.website.com will show an error but www.website.com/index.php?id=1 will show a page I want to be able to show the homepage if there is no 'id' at all. <?php $id = $_GET['id']; if(file_exists("./".$id.".php")) { include ("./".$id.".php"); } else { include ("404.php"); } ?> Any help is appreciated Thanks Link to comment https://forums.phpfreaks.com/topic/235178-simple-dynamic-content-site-help/ Share on other sites More sharing options...
wildteen88 Posted April 30, 2011 Share Posted April 30, 2011 Add an if statement which checks to see if $_GET['id'] isset. If it does then set $id to the value of $_GET['id']. Otherwise set $id to 1 The above translated into PHP code $id = isset($_GET['id']) ? $_GET['id'] : 1; Note the ?: syntax is called a ternary operator (an in-line if/else statement) Link to comment https://forums.phpfreaks.com/topic/235178-simple-dynamic-content-site-help/#findComment-1208606 Share on other sites More sharing options...
debbie-g85 Posted April 30, 2011 Author Share Posted April 30, 2011 Works fine, thank you very much Link to comment https://forums.phpfreaks.com/topic/235178-simple-dynamic-content-site-help/#findComment-1208608 Share on other sites More sharing options...
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