tobitimac Posted May 2, 2011 Share Posted May 2, 2011 how can i make this code to insert a single, multiple and update rows in the database. The code only insert new rows in the database. if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 100000, ",")) !== FALSE) { $num = count($data); $recordCount = @mysql_num_rows("Select * from inventory where itemNumber=".$data[0]); if ($recordCount > 0) { $sql1 = "UPDATE inventory SET itemNumber='$data[1]' AND itemDesc='$data[2]' AND itemDesc='$data[3]' AND quantityHand='$data[4]' AND category='$data[5]' AND Whse='$data[6]' WHERE itemNumber='$data[1]' "; mysql_query($sql1) or die(mysql_error()); } else { $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/ Share on other sites More sharing options...
gizmola Posted May 2, 2011 Share Posted May 2, 2011 Your update syntax is wrong. It should be UPDATE inventory SET itemNumber='$data[1]', itemDesc='$data[2]', .... WHERE... Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1209582 Share on other sites More sharing options...
tobitimac Posted May 2, 2011 Author Share Posted May 2, 2011 This is what i changed it to but still not updating, its only insert new rows. if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 100000, ",")) !== FALSE) { $num = count($data); $recordCount = @mysql_num_rows("Select * from inventory where itemNumber=".$data[0]); if ($recordCount > 0) { $sql1 = "UPDATE inventory SET itemNumber='$data[1]',itemDesc='$data[2]',itemDesc='$data[3]',quantityHand='$data[4]',category='$data[5]',Whse='$data[6]' WHERE itemNumber='$data[1]' "; mysql_query($sql1) or die(mysql_error()); } else { $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1209651 Share on other sites More sharing options...
gizmola Posted May 2, 2011 Share Posted May 2, 2011 Well yes I guess I didn't notice that this line is invalid: $recordCount = @mysql_num_rows("Select * from inventory where itemNumber=".$data[0]); What you need to do is do a query and assign that to a variable that will be the result. Then you can use mysql_num_rows() on the result to see if there is one. Just in terms of advice, don't use the @ until you are sure you know what you're doing as it hides errors. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1209676 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Am not so sure how you want to do it am really new to PHP.. Can you help with this, its really frustrating. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1209696 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 You do something like: $result = mysql_query("SELECT * FROM inventory WHERE itemNumber=$data[0]"); if ($result) { $recordCount = mysql_num_rows($result); if ($recordCount > 0) { // rest of your current code loop here. } else { // your current code. } } else { die(mysql_error()); } Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1209747 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Hi, I used the script but its not updating or inserting new records. What can i do now??? Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210013 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 Let's see the current version of your script. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210018 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Here is my new code $result = mysql_query("SELECT * FROM inventory WHERE itemNumber=".$data[0]); if ($result) { $recordCount = mysql_num_rows($result); echo "$recordCount Rows\n"; if ($recordCount > 0) { // rest of your current code loop here. $sql1 = "UPDATE inventory SET itemNumber='$data[0]',itemDesc='$data[1]',quantityHand='$data[2]',category='$data[3]',Whse='$data[4]' WHERE itemNumber='$data[0]' "; mysql_query($sql1) or die(mysql_error()); } else { // your current code. $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } else { die(mysql_error()); } Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210042 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 Well, your first query can not succeed based on what you have right now, because I don't see anyplace that $data would be getting values from. You used to have: if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 100000, ",")) !== FALSE) { $num = count($data); Did you leave that out? I'd actually like to see your entire script at present rather than a snippet. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210047 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Hi Thanks for your quick response, here is the entire code, its really small code.. <? session_start(); //db connection $db = mysql_connect("xxx", "xxx", "xxx") or die("Could not connect."); if(!$db) die("no db"); if(!mysql_select_db("db70481_mlkishigo",$db)) die("No database selected."); //$row = 0; if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { $num = count($data); $result = mysql_query("SELECT * FROM inventory WHERE itemNumber=".$data[0]); if ($result) { $recordCount = mysql_num_rows($result); echo "$recordCount Rows\n"; if ($recordCount > 0) { // rest of your current code loop here. $sql1 = "UPDATE inventory SET itemNumber='$data[0]',itemDesc='$data[1]',quantityHand='$data[2]',category='$data[3]',Whse='$data[4]' WHERE itemNumber='$data[0]' "; mysql_query($sql1) or die(mysql_error()); } else { // your current code. $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } else { die(mysql_error()); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210054 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 I editted your post to take out your pw's, and here I reformatted your code a little bit, and changed the mysql_error() call in the loop to echo rather than die in the outer loop. I don't see anything overtly incorrect here. Are you getting any errors? What is the output? session_start(); //db connection $db = mysql_connect("xxx", "xxx", "xxx") or die("Could not connect."); if(!$db) die("no db"); if(!mysql_select_db("db70481_mlkishigo",$db)) die("No database selected."); //$row = 0; if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { $num = count($data); $result = mysql_query("SELECT * FROM inventory WHERE itemNumber=".$data[0]); if ($result) { $recordCount = mysql_num_rows($result); echo "$recordCount Rows\n"; if ($recordCount > 0) { // rest of your current code loop here. $sql1 = "UPDATE inventory SET itemNumber='$data[0]',itemDesc='$data[1]',quantityHand='$data[2]',category='$data[3]',Whse='$data[4]' WHERE itemNumber='$data[0]'"; mysql_query($sql1) or die(mysql_error()); } else { // your current code. $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values ('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } else { echo mysql_error(); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210065 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 i used the new code but am getting this error. Unknown column '2X' in 'where clause' i believe its has to do with $result = mysql_query("SELECT * FROM inventory WHERE itemNumber=".$data[0]); Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210073 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 Right at the top under the line: while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { Add var_dump($data); So you can see if the $data array elements match up to what you expect. I'm assuming that if the problem you pointed out above is related to data, it's that when you use itemNumber=, if itemNumber is a numeric data type as defined in your database, then it expects a number. '2X' would not be a number. If it's a character type like a varchar, then you need the quotes around it for the sql to be valid. $result = mysql_query("SELECT * FROM inventory WHERE itemNumber='$data[0]'"); Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210098 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Right at the top under the line: while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { Add var_dump($data); So you can see if the $data array elements match up to what you expect. I'm assuming that if the problem you pointed out above is related to data, it's that when you use itemNumber=, if itemNumber is a numeric data type as defined in your database, then it expects a number. '2X' would not be a number. If it's a character type like a varchar, then you need the quotes around it for the sql to be valid. $result = mysql_query("SELECT * FROM inventory WHERE itemNumber='$data[0]'"); After adding var_dump($data);. i added two two to '$data[0]'" still is not updating or inserting a new row, here is my code below. if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { //var_dump($data); $num = count($data); $result = mysql_query("SELECT * FROM inventory WHERE itemNumber='$data[0]'"); if ($result) { $recordCount = mysql_num_rows($result); echo "$recordCount Rows\n"; if ($recordCount > 0) { // rest of your current code loop here. $sql1 = "UPDATE inventory SET itemNumber='$data[0]',itemDesc='$data[1]',quantityHand='$data[2]',category='$data[3]',Whse='$data[4]' WHERE itemNumber='$data[0]'"; mysql_query($sql1) or die(mysql_error()); } else { // your current code. $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values ('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } else { echo mysql_error(); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210111 Share on other sites More sharing options...
gizmola Posted May 3, 2011 Share Posted May 3, 2011 I actually wanted you to run the var_dump and paste the results here so we can see what the data array contains. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210131 Share on other sites More sharing options...
tobitimac Posted May 3, 2011 Author Share Posted May 3, 2011 Here is what i have, and anytime the value of quantityHand changes, it will insert all the rows again into the mysql, making the mysql to have double row of the same record. if (($handle = fopen('http://mlkishigo.com/sageonline/inventorylist.csv', "r")) !== FALSE) { while (($data = fgetcsv($handle, 900000, ",")) !== FALSE) { var_dump($data); $num = count($data); $result = mysql_query("SELECT * FROM inventory WHERE itemNumber='$data[0]' AND itemDesc='$data[1]'AND quantityHand='$data[2]' AND category='$data[3]' AND Whse='$data[4]'"); if ($result) { $recordCount = mysql_num_rows($result); //echo "$recordCount Rows\n"; if ($recordCount > 0) { // rest of your current code loop here. $sql1 = "UPDATE inventory SET itemNumber='$data[0]',itemDesc='$data[1]',quantityHand='$data[2]',category='$data[3]',Whse='$data[4]' WHERE itemNumber='$data[0]' AND itemDesc='$data[1]'AND quantityHand='$data[2]' AND category='$data[3]'AND Whse='$data[4]'"; mysql_query($sql1) or die(mysql_error()); } else { // your current code. $sql="INSERT into inventory(itemNumber,itemDesc,quantityHand,category,Whse) values ('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')"; mysql_query($sql) or die(mysql_error()); } } else { echo mysql_error(); } } fclose($handle); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210147 Share on other sites More sharing options...
gizmola Posted May 4, 2011 Share Posted May 4, 2011 In your WHERE clause, if there is some combination of columns that can be used to uniquely identify one row from another, then you should use that, omitting the 'AND quantityHand='$data[2]' from the SELECT since it seems that is not what you want. With that said, it seems like this question is morphing, and that we've solved your initial issues. If you're now onto some new problem, please make a new thread with a new title that better reflects what your struggling with, and mark this one solved. Quote Link to comment https://forums.phpfreaks.com/topic/235375-insert-and-update-row-in-mysql/#findComment-1210252 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.