swincher4391 Posted May 6, 2011 Share Posted May 6, 2011 Here are the project of files: So the problem I'm running into is, while php ---> php is fine (it's recovering all of my variables, I've tested with echo), the problem seems to be where I have made a command ./createlisting.sh $itemno $title $header $description $image It reads in $itemno, $title, $header $description just fine, but it fails when I try to send an image. Again I've echoed it out and my $image variable contains the correct image name. When it gets sent to the bash script and the bash script sends it to a "log.txt" it only shows $1 thru $4, excluding the $5. When I try to use the img src to create the image on the page, the outputting echo on the page is <img src ="/images/" /> Which of course is going to result in nothing. What advice can you guys offer me? Thanks! createPage.php: <html> <body> <form enctype="multipart/form-data" action="submitForm.php" method="post"> Item#: <input type="text" name="itemno" value="1" /><br /> Title: <input type="text" name="title" value="My Listing" /><br /> Header: <input type="text" name="header" value="ENTER YOUR LISTING" /><br /> <textarea name="description" cols="60" rows="20"> You will have to use quotes on anything that has more than one word. Sorry! </textarea><br><br /></p> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> Choose an image to upload: <input name="uploadedfile" type="file" /><br /> <input type="submit" value="Submit" /> </form> </body> </html> submitForm.php: <?php $itemno = $_POST["itemno"]; $title = $_POST["title"]; $header = $_POST["header"]; $description = $_POST["description"]; // Where the file is going to be placed $target_path = "/home/images/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $image = basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } $command = "." . "/" . "createlisting.sh"; $param = $itemno . " " . $title . " " . $header . " " . $description; $finalimage = $image . ""; $final = $command . " " . $param . " " . $finalimage; passthru($final); createlisting.sh: #!/bin/bash #Create the page based on the information cd logs echo $1 > log.txt echo $2 >> log.txt echo $3 >> log.txt echo $4 >> log.txt echo $5 >> log.txt cd .. ./createNewDir.sh $(date +%m%d%Y) cd .. cd listings cd $(date +%m%d%Y) mkdir $1 cd $1 echo "<HTML>" > listing.html echo "<Head>" >> listing.html echo "<Title>" >> listing.html echo "$2" >> listing.html echo "</title>" >> listing.html echo "</head>" >> listing.html echo "<body>" >> listing.html echo "<h1>$3</h1><br>" >> listing.html echo "<img src=\"/images/$5\" />" echo "$4" >> listing.html echo "</body>" >> listing.html echo "</html>" >> listing.html cd .. cd .. cd .. cd scripts echo $(date +%d%m%Y); Quote Link to comment https://forums.phpfreaks.com/topic/235712-need-help-sending-php-variables-to-script/ Share on other sites More sharing options...
wildteen88 Posted May 6, 2011 Share Posted May 6, 2011 Any reason why you're creating files with a bash script. PHP has many functions for reading/writing to files. Quote Link to comment https://forums.phpfreaks.com/topic/235712-need-help-sending-php-variables-to-script/#findComment-1211537 Share on other sites More sharing options...
swincher4391 Posted May 6, 2011 Author Share Posted May 6, 2011 That's what I need help with. Not only do I need to create a different named file per each "listing" created, but I need to redirect the form info to format the page according to the way my bash script did. Please help. Quote Link to comment https://forums.phpfreaks.com/topic/235712-need-help-sending-php-variables-to-script/#findComment-1211685 Share on other sites More sharing options...
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