Hobbyist_PHPer Posted May 8, 2011 Share Posted May 8, 2011 Hi all, I am trying to figure out how to add 60 days to a mysql stored DATE, then subtract the current date from that date to see how many days there are... Its for a 60 day trial and when they signed up, it put the date in which they signed up in the database table... Here's what I have, but it's not working... But I can't get it to add 60 days to a mysql stored DATE,... then of course I have to figure out how to do the subtraction... $CustomerSaasDateStarted = $row['CustomerSaasDateStarted']; $CustomerSaasDateStartedPlusSixtyDays = date("Y-m-d", strtotime($CustomerSaasDateStarted, "+60 days")); // Test Output echo 'Date Trial Started: '.date("M d, Y", strtotime($CustomerSaasDateStarted)); echo '<br />'; echo '60 days from Date Trial Started: '.date("M d, Y", strtotime($CustomerSaasDateStartedPlusSixtyDays)); echo '<br />'; Link to comment https://forums.phpfreaks.com/topic/235865-php-time/ Share on other sites More sharing options...
Hobbyist_PHPer Posted May 8, 2011 Author Share Posted May 8, 2011 Ok, figured out how to add 60 days to a mysql date... $CustomerSaasDateStartedPlusSixtyDays = date('M d, Y', strtotime($CustomerSaasDateStarted.' '.'+60 days')); Now just need to figure out how to subtract the current date from that... will post code if I figure it out... Link to comment https://forums.phpfreaks.com/topic/235865-php-time/#findComment-1212455 Share on other sites More sharing options...
Hobbyist_PHPer Posted May 8, 2011 Author Share Posted May 8, 2011 Cannot seem to get a grip on this whole subtracting 2 dates things... I need to find out how many days are left from the subtraction... This gives the wrong output, but like a month's worth... $CustomerSaasDateStarted = $row['CustomerSaasDateStarted']; $CustomerSaasDateStartedPlusSixtyDays = date('Y-m-d', strtotime($CustomerSaasDateStarted.' '.'+60 days')); $TheCurrentDate = date('Y-m-d'); $TheCurrentDate = new DateTime($TheCurrentDate); $CustomerSaasDateStartedPlusSixtyDays = new DateTime($CustomerSaasDateStartedPlusSixtyDays); $DifferenceInterval = $TheCurrentDate->diff($CustomerSaasDateStartedPlusSixtyDays); echo $DifferenceInterval->d.' Days Remaining on Trial<br /><br /> Link to comment https://forums.phpfreaks.com/topic/235865-php-time/#findComment-1212462 Share on other sites More sharing options...
PFMaBiSmAd Posted May 8, 2011 Share Posted May 8, 2011 You can do this all as part of your query - SELECT DATEDIFF(DATE_ADD(CustomerSaasDateStarted, INTERVAL 60 DAY),CURDATE()) as days_remaining A negative value would indicate the current date is past the end of the trial. A positive value would indicate the trial is still in effect. Link to comment https://forums.phpfreaks.com/topic/235865-php-time/#findComment-1212464 Share on other sites More sharing options...
Hobbyist_PHPer Posted May 8, 2011 Author Share Posted May 8, 2011 You can do this all as part of your query - SELECT DATEDIFF(DATE_ADD(CustomerSaasDateStarted, INTERVAL 60 DAY),CURDATE()) as days_remaining A negative value would indicate the current date is past the end of the trial. A positive value would indicate the trial is still in effect. Thank you, that worked perfectly, never thought to do it in the query... Link to comment https://forums.phpfreaks.com/topic/235865-php-time/#findComment-1212500 Share on other sites More sharing options...
Hobbyist_PHPer Posted May 8, 2011 Author Share Posted May 8, 2011 Actually, had to make one minor change to make the amount of days come out right, I didn't notice it at first until I started changing the date in which they signed up... (60 - DATEDIFF(DATE_ADD(CustomerSaasDateStarted, INTERVAL 60 DAY),CURDATE())) as DaysRemaining Link to comment https://forums.phpfreaks.com/topic/235865-php-time/#findComment-1212520 Share on other sites More sharing options...
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