pcw Posted May 19, 2011 Share Posted May 19, 2011 Hi, I got this code which is meant to display the login details of the person that is logged in, however it just displays the details of the last person in the mysql table. I have set up some test logins, so if I login as paul1 the details for paul3 are displayed...confused Anyway, here is the page which displays the details <?php session_start(); // This checks to make sure the session variable is registered // WARNING: DO NOT DELETE THE FOLLOWING LINE OF TEXT if( isset($_SESSION['username']) && isset($_SESSION['sid'])) { // You are free to edit the following code to suit your requirements include_once("../../data/server.php"); include_once("../../lib/userdata.php"); // THIS BIT WORKS AND DISPLAYS THE USERNAME $data = mysql_query("SELECT * FROM members") or die(mysql_error()); while($info = mysql_fetch_array( $data )) { include("../../lib/userinfo.php"); //////////////////////////////////////////// WARNING: YOU SHOULD NOT EDIT ANYTHING ABOVE THIS LINE //////////////////////////////////////////////////////// ECHO <<<PAGE <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>$siteName</title> <link rel="stylesheet" href="../../userstylesheet.css" type="text/css" /> </head> <div id="page"> <img alt="" src="../../images/leftCurve" height="6" width="6" id="left" /> <img alt="" src="../../images/rightCurve.gif" height="6" width="6" id="right" /> <div id="pageName"> <h1>$siteName</h1> </div> <div id="pageNav"> <div id="sectionLinks"> <a href="profile.php?username=$username">My Profile</a> <a href="modify.php?username=$username">Personal Details</a> <a href="message.php?username=$username">Messages</a> <a href="../../logout.php?username=$username">Logout</a></div> </div> <div id="content"> <div class="feature"> <h2>Welcome $username </h2> <p>This is the demonstration home.html template. You are free to edit this or any of the other templates to suit your own needs. </p> <p>This is the first page your member will see once they have logged in. </p> <p>If you look at the code for this page, you will see that all HTML code is placed between the ***PAGE and PAGE; tags. Please note that the three * should be replaced with the < character. This format must be kept to ensure that the user variables work. Changing this format may result in errors being returned.</p> <p>You may call member information using the $ tag and the variable name eg $ firstname without the space, will show the members first name, such as $firstname</p> <p>For any information please visit our site http://www.membersitemaker.co.uk. User guides will be added shortly and the forum will soon be full of help. </p> </div> </div> <div id="information"> <a href="#">About Us</a> | <a href="#">Site Map</a> | <a href="#">Privacy Policy</a> | <a href="#">Contact Us</a> | ©2011 $siteName </div> </div> </body> </html> PAGE; } //////////////////////////////////////// WARNING: DO NOT DELETE ANYTHING BELOW THIS LINE ////////////////////////////////////////////////////////// } else { // This will redirect the user to the login page if the session variables do not exist header( "Location: ../../../login.html" ); } ?> And here is the code for userdata.php <?php // Decode sitename function decode_variable(&$siteName) { $siteName = urldecode($siteName); $siteName = str_replace('%20',' ',$siteName); return $siteName; } decode_variable($siteName); // Connnect to MySQL database include_once("../../data/mysql.php"); $mysqlPassword = (base64_decode($mysqlpword)); $db = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die ("Error connecting to database"); mysql_select_db("$dbname", $db) or die ("An error occured when connecting to database"); // Carry out MySQL query ?> and userinfo.php <?php $username = $info['username']; $firstname = $info['firstname']; $lastname = $info['lastname']; $address = $info['address']; $town = $info['town']; $county = $info['county']; $postcode = $info['postcode']; $email = $info['email']; $birth_year = $info['birth_year']; $country = $info['country']; $telephone_number = $info['telephone_number']; $mobile_number = $info['mobile_number']; $nickname = $info['nickname']; As always, your help is much appreciated Paul Quote Link to comment Share on other sites More sharing options...
fugix Posted May 19, 2011 Share Posted May 19, 2011 you need to add a where clause in your mysql_query so it know whose info to grab...also since you are only grabbing one users data...a while loop is not needed..e.g $data = mysql_query("SELECT * FROM members WHERE username = '$username'") Quote Link to comment Share on other sites More sharing options...
pcw Posted May 19, 2011 Author Share Posted May 19, 2011 Thanks Fugix, it worked Quote Link to comment Share on other sites More sharing options...
fugix Posted May 19, 2011 Share Posted May 19, 2011 Thanks Fugix, it worked excellent Quote Link to comment Share on other sites More sharing options...
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