cnl83 Posted May 19, 2011 Share Posted May 19, 2011 If you goto http://www.actionfx.net/bfd/photos.php you will see that im trying to show an rss feed from http://picasaweb.google.com/data/feed/base/user/114565750484201639035?alt=rss&kind=album&hl=en_US&access=public My code works well if its just text on the rss but it does not work on this particular rss. I want the photos to show up on my page also. Im hoping someone here can be so kind to help me out with this coding. Below is my code. <?php $feed_url = "http://picasaweb.google.com/data/feed/base/user/114565750484201639035?alt=rss&kind=album&hl=en_US&access=public"; // INITIATE CURL. $curl = curl_init(); // CURL SETTINGS. curl_setopt($curl, CURLOPT_URL,"$feed_url"); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, 0); // GRAB THE XML FILE. $xmlTwitter = curl_exec($curl); curl_close($curl); // SET UP XML OBJECT. // Use either one of these, depending on revision of PHP. // Comment-out the line you are not using. //$xml = new SimpleXMLElement($xmlTwitter); $xml = simplexml_load_string($xmlTwitter); // How many items to display $count = 10; // How many characters from each item // 0 (zero) will show them all. $char = 100; foreach ($xml->channel->item as $item) { if($char == 0){ $newstring = $item->description; } else{ $newstring = substr($item->description, 0, $char); } if($count > 0){ //in case they have non-closed italics or bold, etc ... echo"</i></b></u></a>\n"; echo" <div style='font-family:verdana; font-size:.12;'> <b>{$item->title}</b><br /> $newstring ... <span class='redlink' id='redlink' style='redlink'> <a href='{$item->guid}'>read more</a> </span> <br /><br /> </div> "; } $count--; } ?> Link to comment https://forums.phpfreaks.com/topic/236868-showing-rss-feed-with-photos-on-another-page/ Share on other sites More sharing options...
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