lingo5 Posted May 31, 2011 Share Posted May 31, 2011 Hi, I want to echo an image depending on a value. This is the code I'm using <?php if ($row_cliente_RS['estadofactura_titulo']) == 'yes' echo '<img src="img/pagada.jpg" width="70" height="15">'; ?> ...but nothing echoes. What am I doing wrong? Thanks Quote Link to comment https://forums.phpfreaks.com/topic/238018-help-printing-an-image/ Share on other sites More sharing options...
xyph Posted May 31, 2011 Share Posted May 31, 2011 http://www.tizag.com/phpT/if.php Quote Link to comment https://forums.phpfreaks.com/topic/238018-help-printing-an-image/#findComment-1223053 Share on other sites More sharing options...
HDFilmMaker2112 Posted May 31, 2011 Share Posted May 31, 2011 Hi, I want to echo an image depending on a value. This is the code I'm using <?php if ($row_cliente_RS['estadofactura_titulo']) == 'yes' echo '<img src="img/pagada.jpg" width="70" height="15">'; ?> ...but nothing echoes. What am I doing wrong? Thanks The closing ) in your if statement is in the wrong place: if ($row_cliente_RS['estadofactura_titulo'] == 'yes') and you should wrap the content for the if statement in {} brackets: <?php if ($row_cliente_RS['estadofactura_titulo']== 'yes'){ echo '<img src="img/pagada.jpg" width="70" height="15">'; } ?> Quote Link to comment https://forums.phpfreaks.com/topic/238018-help-printing-an-image/#findComment-1223056 Share on other sites More sharing options...
lingo5 Posted May 31, 2011 Author Share Posted May 31, 2011 Thanks HDFilmmaker, that solved it. Thanks to you too Xyph, I will take a look at that. Quote Link to comment https://forums.phpfreaks.com/topic/238018-help-printing-an-image/#findComment-1223059 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.