unable to return array

[narjis]

I am opening a connection with mysqli and passing the returning object to another function which returns the array of the object passed but it is not giving correct result.

Here is the code:

function convert_to_array($arrObj){
$res_array = array();
for ($count=0; $row = $arrObj->fetch_assoc(); $count++){
	$res_array[$count] = $row;
	}	
	return $res_array;
}
function getUser($email,$pass)
{
$conn = db_connect();
$query ="select * from users where Password='".$pass."' and Email='".$email."'";
$result = @$conn->query($query);
$num = @$result->num_rows;
if($num==0)
echo "NoT OK";
else{
echo "OK";
$result = convert_to_array($result); 
echo ("$num");
return $result;
}function getUser($email,$pass)
{
$conn = db_connect();
$query ="select * from users where Password='".$pass."' and Email='".$email."'";
$result = @$conn->query($query);
$num = @$result->num_rows;
if($num==0)
echo "NoT OK";
else{
echo "OK";
$result = convert_to_array($result); 
echo ("$num");
return $result;
}

[GingerRobot]

Well the first thing I notice is that you're suppressing errors on the function calls. Are you sure you wanted to do that? What happens if your query is not executed successfully?

[narjis]

It returns true for the valid user but does not convert this object to array.

[mikosiko]

take the @ out of your calls to functions as was suggested.

 

in the code that you posted...is there a copy/paste problem?.. you have the function getUser() twice

 

...which returns the array of the object passed but it is not giving correct result...

why?... details...