Link as submit button

[codingmasterRS]

Hi, I have tried this

<a href="document.['formname'].submit(); return false;">Go</a>

 

except it is returning a Not Found, as it redirects the browser to http://mydomain.com/document.%5B%27shareform%27%5D.submit%28%29;%20return%20false;

[Alex]

That should be the value of the onclick attribute, not href.

[codingmasterRS]

Okay so I have this

 

index.php

<form action="test.php" method="post" name="shareform">
<textarea name="text"></textarea>
<a href="#" onclick="document.['shareform'].submit(); return false;">Go</a>
</form>
<?php session_strat(); echo $_SESSION['text'];?>

 

test.php

<?php
session_start();
$_SESSION['text'] = $_POST['text'];

 

But its not working, even after refresh of index.php, not processing correctly. Any ideas why?

 

Thanks for the help so far

[Alex]

You misspelled session_start():

 

<?php session_strat(); echo $_SESSION['text'];?>

 

You would also have to put session_start(); before any other output.

 

To access the form you need to use

 

document.forms['shareform']

 

not

 

document.['shareform']

[codingmasterRS]

okay now I have that working, now I am trying the AJAX/jQuery submit part

 

 

so I have this code

  /* attach a submit handler to the form */
  $("#shareform").submit(function(event) {

    /* stop form from submitting normally */
    event.preventDefault(); 
        
    /* get some values from elements on the page: */
    var $form = $( this ),
        term = $form.find( 'input[name="text"]' ).val(),
        url = $form.attr( 'action' );

    /* Send the data using post and put the results in a div */
$.post("test.php");
  });

 

but is seems not to be working, and Im not entirely sure why

 

FROM http://api.jquery.com/jQuery.post/

 

Thanks for all the help so far Alex

[Alex]

You'll need to specify the data to be sent in the request, and a callback function to be called when the response returns. Something like this:

 

$.post(url, {'text': term}, function(data) {
    $('#somedivid').html(data);
});

[codingmasterRS]

what would #somedivid be??

[Alex]

It would be the only thing you needed if you just wanted to request the page and do nothing else. But you want to request the page with the post data ($_POST['text']), and put the result of that request (whatever that file outputs) in a div, then you'll need something different.

 

"somedivid" would be the id of the div that you want to post the result of the response in, assuming that's what you want to do.

 

If I was mistaken and you don't want to do anything with the result of the request just remove the last parameter, the success function, from the $.post() call. Making it:

 

$.post(url, {'text': term});

[codingmasterRS]

I just want to post the field off to text.php for placing in a session and thats it, no auto refresh no place auto in div

[codingmasterRS]

Current code

    			<form action="test.php" id="shareform" method="post" name="shareform">
			<textarea id="share" name="share" onDblClick="alert('double clicked');"></textarea>
			<a href="#" onclick="document.forms['shareform'].submit(); return false;" class="share">Share</a>
		</form>

 

  $("#shareform").submit(function(event) {

    /* stop form from submitting normally */
    event.preventDefault(); 
        
    /* get some values from elements on the page: */
    var $form = $( this ),
        term = $form.find( 'input[name="share"]' ).val(),
        url = $form.attr( 'action' );

    /* Send the data using post and put the results in a div */
$.post(url, {'share': term});
  });

 

 

 

still NOT working

[codingmasterRS]

It needs to work like an AJAX submission, so you NEVER leave this page once the data is submitted or as it is being submitted.