ArizonaJohn Posted June 24, 2011 Share Posted June 24, 2011 I would like to run a MySQL query each time a Facebook Like button is clicked on a page. I already know that FB.Event.subscribe('edge.create', function(response) {} is used to execute something when a Like button is clicked. My problem is that I don't know Javascript / AJAX. What simple Javascript/AJAX code that I can but in the curly brackets of the FB.event that will just run the MySQL query below? My understanding is that I might need to get some sort of JQuery library, which is fine. Thanks in advance, John The relevant code on the page: <script src="http://connect.facebook.net/en_US/all.js"></script> <?php session_start(); $uid = $_SESSION['loginid']; $_SESSION['submissionid'] = $submissionid; echo '<div id="fb-root"></div>'; echo "<script> window.fbAsyncInit = function() { FB.init({appId: 'your app id', status: true, cookie: true, xfbml: true}); }; (function() { var e = document.createElement('script'); e.async = true; e.src = document.location.protocol + '//connect.facebook.net/en_US/all.js'; document.getElementById('fb-root').appendChild(e); }()); echo '</script>"; echo '<html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml">'; echo '<script src="http://connect.facebook.net/en_US/all.js#xfbml=1"></script><fb:like href="" send="true" layout="button_count" width="450" show_faces="false" font="arial"></fb:like>'; The MySQL query that I would like to run each time a Like button is clicked: mysql_query("INSERT INTO fblikes VALUES (NULL, '$submissionid', '$uid', NULL)"); Quote Link to comment Share on other sites More sharing options...
gizmola Posted June 24, 2011 Share Posted June 24, 2011 Javascript runs "clientside" in the user's browser. PHP runs on a server. Right and test a php script that accepts the values you require for the mysql insert. Be sure that you have error checking, and the same type of security you would have if this was going to be a form submission via post. In other words, there is nothing magic about javascript that makes it more secure and less prone to tampering or malicious input. Yes I'd suggest you use jquery. This may look confusing to you as a php programmer, due to their use of $. Forget that php uses $ for variables. jQuery is constructed as one giant class named jQuery, and the $ is an alias for "jquery". So when you see: $.post("test.php", { name: "John", time: "2pm" } ); Keep in mind that this is the same as: jQuery.post("test.php", { name: "John", time: "2pm" } ); Take a look at the examples on http://api.jquery.com/jQuery.post/ and see if you can figure out what you specifically need to do. jQuery can also be of help with what you'll need to with the like button itself, as it will help you grab the button click and execute the wrapper function you'll need. This should explain it very simply: http://www.learningjquery.com/2008/03/working-with-events-part-1 As much as these api's hide complexity, there is a point at which you just have to bite the bullet and learn a modicum of javascript syntax and rules to pull this type of thing off typically. Quote Link to comment Share on other sites More sharing options...
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