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Hi,

can anyone show me the procedure to make this happen, i am new on this.

emp_id--Name

1-------AA

2-------AB

3-------AC

4-------AD

5-------AE

6-------AF

7-------AZ

 

2)table job_done

emp_id --- date - --job_done --score

1 - - - 22-06-2011 -------1-------50

3 - - - 23-06-2011--------1-------25

5 - - - 24-06-2011--------1-------70

1 - - - 25-06-2011--------1-------50

3 - - - 26-06-2011--------1-------25

 

3)table job_failed

emp_id - -- date -- job_failed

2 - - - 22-06-2011 -------1

4 - - - 24-06-2011 -------1

6 - - - 26-06-2011 -------1

5 - - - 21-06-2011 -------1

 

Now how can i get result like

Name - -job_done - job_failed -score - job_handled - success_rate

AA---------2----------0----------50-------- 2 -----------100%

AB---------0----------1----------0 -------- 1 ----------- 0%

AC---------2----------0----------25-------- 2 -----------100%

AD---------0----------1----------0 -------- 1 ----------- 0%

AE---------1----------1----------70-------- 2 ----------- 50%

AF---------0----------1----------0 -------- 1 ----------- 0%

 

1)here date will not visible but i must able to search by date from both job_done and failed date by one selected range but i'm only can manage with one date either table 2 or 3 .

2)if a employee like 'AZ' not give any job will exclude from report.

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https://forums.phpfreaks.com/topic/240479-how-to-make-this-query-with-3-table/
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Hello Mikosiko,

Here is my Query's received from one great. and only resolved half of problem

 

select employee.name, ifnull(done,0) done,ifnull(failed,0) failed,ifnull(score,0) score

from employee

left join (select emp_id,sum(job_done) done,avg(score) score from job_done group by emp_id) done using(emp_id)

left join (select emp_id, sum(job_failed) failed from job_failed group by emp_id) failed using(emp_id)

order by employee.name;

 

Here im unable to add sum of done+failed = total, done/total*100= xx%. and finally combine both date in a single column so that i can search by date.

 

can you please give some code to finish it?

Thanks 

here is your fish:  .... replace any wrong column name with your own, and with the proper dates that you want (or variables)

 

select a.name,
       COUNT(b.job_done) AS job_done,
       COUNT(c.job_failed) AS job_failed,
       COUNT(b.job_done) + COUNT(c.job_failed) AS job_handled,
       (COUNT(b.job_done) * 100) / (COUNT(b.job_done) + COUNT(c.job_failed)) AS success_rate
FROM employee AS a
LEFT JOIN job_done AS b ON b.emp_id = a.emp_id AND b.fecha between '2011-06-21' AND '2011-06-26'
LEFT JOIN job_failed AS c ON c.emp_id = a.emp_id  AND c.fecha between '2011-06-21' AND '2011-06-26'
GROUP BY a.name
HAVING job_handled > 0;

 

anything else is for you to work on.

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