Quick query for PHP

[anevins]

in the following code snippet, how does variable 'a' hold value of 1? I don't understand how that 1 gets in that variable.

 

function test($a){
$c = 2;
echo $c;
echo $a;
return 6;

}

$c = 1;
echo $c;

echo test($c);
echo $c;

exit();

[monkeytooth]

somewhere when the functions is called ie:

 

 

test(55); $a will be 55

 

test(65); $a will be 65

 

test(75); $a will be 75

 

test(99); $a will be 99

 

[anevins]

In my example, I don't see an integer in parenthesis next to the function, so I can't make sense of it that way.

[monkeytooth]

Ahh didn't pay mind to the whole thing..

 

Take note to your setting of the $c= variable 1 one.. then 3 lines down.. echo test($c); $c by the time it reaches the call to the function is defined as 1, so it is being passed off to the function as 1..

 

function test($a).. $a is contained to the function itself its a static variable you can use within the function itself. Lets try this..

 

 

function monkey($tooth){

if(!is_numeric($tooth)){$output = "Tooth is not Numeric, please enter a number and try again";}
else{

$output = $tooth+20; //taking the numeric value of $tooth and adding 20 to it..

}
return $output;
}

echo monkey(80);
echo "<br />";
echo monkey("abc");

[monkeytooth]

Another thing worth mentioning

 

exit();

 

Not the best way to end your scripts especially if your going to include scripts within scripts via include(), include_once(), require(), require_once().. exit will just halt your scripts rending from the second its executed so any lines there after included via other files or within the same script will not render.

[anevins]

ok what does $a have to do with $c? I can see how by the time I reach the function, $c has the value of 1 so therefore $a has value of 1?

 

I just dont know how that links up, why arent they different?

 

[anevins]

bump

[TeNDoLLA]

Hope this explanation helps...

// Define function with parameter
function test($thisIsParameter1)
{
// This is the parameter one that u pass to the function,
// dosnt matter what the parameter is called outside the function
// Inside the function it will be $thisIsParameter1.
echo $thisIsParameter1; // will echo out 123
}

$abc = '123';
test($abc) // Use function and pass one parameter $abc to it

[jcbones]

Variable Scope in PHP