phpnerd Posted July 8, 2011 Share Posted July 8, 2011 I want to use XML to dynamic generate a menu using jqtouch. But it does not work. My target is display same result as this static page <html> <head> <title>Cloth Store</title> <link type="text/css" rel="stylesheet" media="screen" href="jqtouch/jqtouch.css"> <link type="text/css" rel="stylesheet" media="screen" href="themes/jqt/theme.css"> <script type="text/javascript" src="jqtouch/jquery.1.3.2.min.js"></script> <script type="text/javascript" src="jqtouch/jqtouch.js"></script> <script type="text/javascript"> var jQT = new $.jQTouch(); </script> </head> <body> <div id="home"> <div class="toolbar"> <h1>Cloth Store</h1> </div> <ul class="edgetoedge"> <li class="arrow"><a href="#books">Books</a></li> <li class="arrow"><a href="#contactus">Contactus</a></li> </ul> </div> <div id="cloth"> <div class="toolbar"> <h1>Books</h1> <a class="button back" href="#">Back</a> </div> <p>We are a US-based organization providing a wide variety of books at a reasonable price</p> </div> <div id="contactus"> <div class="toolbar"> <h1>Contact Us</h1> <a class="button back" href="#">Back</a> </div> <p>XYZ Book Company</p> <p>11 Books Street, NY, NY 10012 </p> <p>USA</p> </div> </body> </html> I want to make the menu changed based on XML. therefore, i change the above one to 2 parts. HTML: <html> <head> <title>Cloth Store</title> <link type="text/css" rel="stylesheet" media="screen" href="jqtouch/jqtouch.css"> <link type="text/css" rel="stylesheet" media="screen" href="themes/jqt/theme.css"> <script type="text/javascript" src="jqtouch/jquery.1.3.2.min.js"></script> <script type="text/javascript" src="jqtouch/jqtouch.js"></script> <script type="text/javascript"> var jQT = new $.jQTouch(); var xhr =new XMLHttpRequest(); xhr.open("GET","text.xml",true); xhr.send(); var txt1=" <div class=\"toolbar\"><h1>CLC Plus</h1></div><ul class=\"edgetoedge\">"; var txt2=""; xhr.onreadystatechange = function(){ if(xhr.readyState == 4){ xmlDoc=xhr.responseXML; x=xmlDoc.getElementsByTagName("name"); y=xmlDoc.getElementsByTagName("desc"); for (i=0;i<x.length;i++) { txt1=txt1 + "<li class=\"arrow\"><a href=\"#" + x.firstChild.nodeValue + "\">" + x.firstChild.nodeValue + "</a></li>"; txt2=txt2 + "<div id=\"" +x. firstChild.nodeValue + "</div><div class=\"toolbar\" align=right><h1>"+ x.firstChild.nodeValue+"</h1><a class=\"button back\" href=\"#\">Back</a></div><p>"+ y.firstChild.nodeValue+"</p>"; txt2 = txt2 + "</div>"; } txt1=txt1 + "</ul>"; document.getElementById('home').innerHTML = txt1; document.getElementById('content').innerHTML = txt2; } } </script> <body> <div id="home" class="current"> </div> <div id="content"> </div> </body> </html> XML: <?xml version="1.0" ?> <company> <name>Cloth</name><desc>We are a US-based organization providing a wide variety of books at a reasonable price</desc> <name>Contactus</name><desc><p>XYZ Book Company</p><p>11 Books Street, NY, NY 10012 </p><p>USA</p></desc> </company> Quote Link to comment https://forums.phpfreaks.com/topic/241395-getting-jqtouch-error-when-using-xml/ Share on other sites More sharing options...
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