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how to display images when stored link in mysql database


mark103

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hi guys,

 

i need your help. i has been searching through on google as i am looking for a php code where i can just stored the images link in the mysql database table, and then display the images. Most of the search results on google they are for stored the images in mysql which is a pretty bad idea. I just want to store the images link in mysql and display the images in php.

 

 

I can't find it, please can you help?

 

 

Cheers.

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Thanks for your quick replied jkewlo and thanks for your help, do you know how I can set the description text next to the images without set them under the images?

 

something got to do with this line:

 

 

  echo "<img src ='".$image_path."'>",  "<p id='text_description'>", $row['text_description'] . "</p>" ;

 

 

here's the current code:

 

<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbusername');
    define('DB_PASSWORD', 'mydbpassword');
    define('DB_DATABASE', 'mydbname');

    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }   

  function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $username = clean($_GET['user']);
    $pass = clean($_GET['pass']);


    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {

$insert = array();
if(isset($_GET['user'])) {
    $insert[] = 'username = \'' . clean($_GET['user']) .'\'';
}
if(isset($_GET['pass'])) {
    $insert[] = 'pass = \'' . clean($_GET['pass']) . '\'';
}



if (count($insert)>0) {
   $names = implode(',',$insert);


if($username) {
  $qrytable1="SELECT username, images, text_description FROM user_list WHERE username='$username'";
  $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());

while ($row = mysql_fetch_array($result1)) {
  $image_path = $row['images'];
  echo "<img src ='".$image_path."'>",  "<p id='text_description'>", $row['text_description'] . "</p>" ;
  }
}
}
}
?>

 

 

Any help would be much appreciated! :)

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