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I am getting this error

 

 

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /path/to/rockslider.inc.php on line 6

 

With this code

 

 

<?php

$sql = mysql_query("SELECT * FROM ava_slider ORDER BY id desc LIMIT 5");


while($row = mysql_fetch_array($sql)) {

$rock_slider['title'] = $row['name'];
$rock_slider['url'] = $row['url'];
$rock_slider['description'] = $row['description'];
$rock_slider['image'] = $row['image'];

include $_SERVER['DOCUMENT_ROOT'] . '/includes/rock/rockslider.php';
}
?>

 

 

Any help

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Pretty much just what the error says.  See link in my signature about mysql problems.

 

Okay

 

this is the error

 

Could not successfully run query (Resource id #38) from DB: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #38' at line 1

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Seems to be unhappy with your query, although I don't understand that error message.  What is the exact code you have right now?

 

<?php
$sql = mysql_query("SELECT * FROM ava_games ORDER BY id desc LIMIT 5");
$row = mysql_query($sql);
if (!$row) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();
    exit;
}

while($row = mysql_fetch_array($sql)) {

$rock_slider['title'] = $row['name'];
$rock_slider['url'] = $row['url'];
$rock_slider['description'] = $row['description'];
$rock_slider['image'] = $row['image'];

include $_SERVER['DOCUMENT_ROOT'] . '/includes/rock/rockslider.php';
}
?>

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https://forums.phpfreaks.com/topic/242158-error-calling-array/#findComment-1243602
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You are calling a query on a query.  Change $sql to this:

$sql = "SELECT * FROM ava_games ORDER BY id desc LIMIT 5";

 

Now

 

 

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/hameda/public_html/gametako/includes/rock/rockslider.inc.php on line 13

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You are calling a query on a query.  Change $sql to this:

$sql = "SELECT * FROM ava_games ORDER BY id desc LIMIT 5";

 

Now

 

 

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/hameda/public_html/gametako/includes/rock/rockslider.inc.php on line 13

 

 

 

this is current

 

<?php
$sql = "SELECT * FROM ava_games ORDER BY id desc LIMIT 5";
$row = mysql_query($sql);
if (!$row) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();
    exit;
}

while($row = mysql_fetch_array($sql)) {

$rock_slider['title'] = $row['name'];
$rock_slider['url'] = $row['url'];
$rock_slider['description'] = $row['description'];
$rock_slider['image'] = $row['image'];

include $_SERVER['DOCUMENT_ROOT'] . '/includes/rock/rockslider.php';
}

?>

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https://forums.phpfreaks.com/topic/242158-error-calling-array/#findComment-1243608
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This worked

 

<?php
$sql = "SELECT * FROM ava_games ORDER BY id desc LIMIT 5";
$result = mysql_query($sql);


while($row = mysql_fetch_array($result)){

$rock_slider['title'] = $row['name'];
$rock_slider['url'] = $row['url'];
$rock_slider['description'] = $row['description'];
$rock_slider['image'] = $row['image'];

include $_SERVER['DOCUMENT_ROOT'] . '/includes/rock/rockslider.php';
}
?>

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https://forums.phpfreaks.com/topic/242158-error-calling-array/#findComment-1243614
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