Get_Broswer conditional

[davery]

Greetings, I'm using the get_browser function that can determine what browser the user is using. The following code will display the name, version and platform of the browser:

<?php
function getBrowser() 
{ 
    $u_agent = $_SERVER['HTTP_USER_AGENT']; 
    $bname = 'Unknown';
    $platform = 'Unknown';
    $version= "";

    //First get the platform?
    if (preg_match('/linux/i', $u_agent)) {
        $platform = 'linux';
    }
    elseif (preg_match('/macintosh|mac os x/i', $u_agent)) {
        $platform = 'mac';
    }
    elseif (preg_match('/windows|win32/i', $u_agent)) {
        $platform = 'windows';
    }
    
    // Next get the name of the useragent yes seperately and for good reason
    if(preg_match('/MSIE/i',$u_agent) && !preg_match('/Opera/i',$u_agent)) 
    { 
        $bname = 'Internet Explorer'; 
        $ub = "MSIE"; 
    } 
    elseif(preg_match('/Firefox/i',$u_agent)) 
    { 
        $bname = 'Mozilla Firefox'; 
        $ub = "Firefox"; 
    } 
    elseif(preg_match('/Chrome/i',$u_agent)) 
    { 
        $bname = 'Google Chrome'; 
        $ub = "Chrome"; 
    } 
    elseif(preg_match('/Safari/i',$u_agent)) 
    { 
        $bname = 'Apple Safari'; 
        $ub = "Safari"; 
    } 
    elseif(preg_match('/Opera/i',$u_agent)) 
    { 
        $bname = 'Opera'; 
        $ub = "Opera"; 
    } 
    elseif(preg_match('/Netscape/i',$u_agent)) 
    { 
        $bname = 'Netscape'; 
        $ub = "Netscape"; 
    } 
    
    // finally get the correct version number
    $known = array('Version', $ub, 'other');
    $pattern = '#(?<browser>' . join('|', $known) .
    ')[/ ]+(?<version>[0-9.|a-zA-Z.]*)#';
    if (!preg_match_all($pattern, $u_agent, $matches)) {
        // we have no matching number just continue
    }
    
    // see how many we have
    $i = count($matches['browser']);
    if ($i != 1) {
        //we will have two since we are not using 'other' argument yet
        //see if version is before or after the name
        if (strripos($u_agent,"Version") < strripos($u_agent,$ub)){
            $version= $matches['version'][0];
        }
        else {
            $version= $matches['version'][1];
        }
    }
    else {
        $version= $matches['version'][0];
    }
    
    // check if we have a number
    if ($version==null || $version=="") {$version="?";}
    
    return array(
        'userAgent' => $u_agent,
        'name'      => $bname,
        'version'   => $version,
        'platform'  => $platform,
        'pattern'    => $pattern
    );
} 

// now try it
$ua=getBrowser();
$yourbrowser= "Your browser: " . $ua['name'] . " " . $ua['version'] . " on " .$ua['platform'] . " reports: <br >" . $ua['userAgent'];
print_r($yourbrowser);
?>

 

I'm trying to add an "if" conditional to say that when the user is using the Mozilla Firefox browser, print the text "Hello World". I just recently tried adding this before the ?> but no luck:

if ($yourbrowser == "Mozilla Firefox") {
print("Hello World");
}

 

Any help would be greatly appreciated.

[TeNDoLLA]

Should not it be

if ($ua['name'] == "Mozilla Firefox") {
    print("Hello World");
}

[davery]

Yes!! It worked! Thank you......Now instead of the "hello world", I wanna display a stylesheet that will show in Firefox.

[TeNDoLLA]

To do that you would just echo out the code for linking the stylesheet in your page like you would echo out any HTML instead of the hello world.

[davery]

What I need is actually not a stylesheet but a php file. How would I link to a php file inside of php?

[TeNDoLLA]

Using require_once() or include_once(). http://fi.php.net/manual/en/function.include-once.php

[davery]

The problem lies within Firefox. Theres a form on the website that is aligned completely off the page in Firefox. In Chrome, its aligned within the space that it should be. Its the same code, just different browsers. Im using Firefox 5.0.1 btw.