jQuery get multiple outputs from PHP file

[fishbaitfood]

Hi all,

 

I'm using jQuery to retrieve aditional data from a database, when a name is selected from the dropdown box, without page refresh.

Now my problem is, that I don't know how to get multiple 'outputs' generated by the php file, which processes this.

 

So, in short, I want multiple outputs in different form fields.

 

I guess it's something very simple, but I can't get it to work.

 

 

What I have so far, but isn't working:

 

jQuery + html

<script type="text/javascript">
function get(){
	$.post('data.php', { name: form.name.value },
		function(tel){
			$("#tel").val(output);
			$("#email").val(output);
			$("#adres").html(output);
			$("#adres").append(output);
			$("#adres").append(output);
			$("#adres").append(output);
		}
		function(email){
			$("#email").val(output);
		}
		function(street){
			$("#adres").html(output);
		}
		function(postcode){
			$("#adres").append(output);
		}
		function(city){
			$("#adres").append(output);
		}
		function(country){
			$("#adres").append(output);
		}
	);
}
</script>

<form name="form">
<select name="name">
	<option></option>
	<?php
		while($row = mysql_fetch_array($result)){
			echo '<option>'.$row['name'].'</option>';
		}
	?>
</select>

<input id="tel" type="text" name="tel" />
<input id="email" type="text" name="email" />
<textarea id="adres" name="adres"></textarea>

<input type="button" value="Autofill" onClick="get();" />
<input type="submit" name="add" value="Add" />
</form>

 

 

data.php

<?php
include_once('verbinding.inc.php');
$con = mysql_connect(MYSQL_SERVER, MYSQL_USERNAME, MYSQL_PASSWORD) or die ("Verbinding mislukt: " . mysql_error());

$name = $_POST['name'];

mysql_select_db("cre8") or die ("Kon de database niet openen: " . mysql_error());

$nr = mysql_query("SELECT nr FROM clients WHERE name = '$name'");
$nr_num_rows = mysql_num_rows($nr);

$tel = mysql_query("SELECT tel_gsm FROM clients WHERE name = '$name'");
$tel_num_rows = mysql_num_rows($tel);
$email = mysql_query("SELECT email FROM clients WHERE name = '$name'");
$email_num_rows = mysql_num_rows($email);

$street = mysql_query("SELECT adres FROM clients WHERE name = '$name'");
$street_num_rows = mysql_num_rows($street);
$postcode = mysql_query("SELECT postcode FROM clients WHERE name = '$name'");
$postcode_num_rows = mysql_num_rows($postcode);
$city = mysql_query("SELECT city FROM clients WHERE name = '$name'");
$city_num_rows = mysql_num_rows($city);
$country = mysql_query("SELECT country FROM clients WHERE name = '$name'");
$country_num_rows = mysql_num_rows($country);

$btw = mysql_query("SELECT btw FROM clients WHERE name = '$name'");
$btw_num_rows = mysql_num_rows($btw);

function tel(){
	if($name==NULL)
		echo '';
	else
	{
		if($tel_num_rows==0)
			echo '';
		else 
		{
			$tel = mysql_result($tel, 0);
			echo $tel;
		}
	}
}
function email(){
	if($name==NULL)
		echo '';
	else
	{
		if($email_num_rows==0)
			echo '';
		else 
		{
			$email = mysql_result($email, 0);
			echo $email;
		}
	}
}
function street(){
	if($name==NULL)
		echo '';
	else
	{
		if($street_num_rows==0)
			echo '';
		else 
		{
			$street = mysql_result($street, 0);
			echo "$street<br />";
		}
	}
}
function postcode(){
	if($name==NULL)
		echo '';
	else
	{
		if($postcode_num_rows==0)
			echo '';
		else 
		{
			$postcode = mysql_result($postcode, 0);
			echo "$postcode ";
		}
	}
}
function city(){
	if($name==NULL)
		echo '';
	else
	{
		if($city_num_rows==0)
			echo '';
		else 
		{
			$city = mysql_result($city, 0);
			echo "$city<br />";
		}
	}
}
function country(){
	if($name==NULL)
		echo '';
	else
	{
		if($country_num_rows==0)
			echo '';
		else 
		{
			$country = mysql_result($country, 0);
			echo $country;
		}
	}
}
function btw(){
	if($name==NULL)
		echo '';
	else
	{
		if($btw_num_rows==0)
			echo '';
		else 
		{
			$btw = mysql_result($btw, 0);
			echo $btw;
		}
	}
}
?>

 

 

[fishbaitfood]

As far as I know, the problem is with the jQuery code.

I just need to know how I can get all the different php functions, instead of 'output'.

And as simple as just putting the function name, doesn't work.

[fishbaitfood]

Anyone?

 

I can't find anything about it the way I want to do it. And it's probably really easy to accomplish. 

 

Thanks.

[nogray]

Instead of using echo in your php, you would create an array with all the outpust - e.g. array('email'=>'my_email@domain.com', 'address'=>'my_adddress');

 

When you finish collecting the data, use json_encode to transfer the array into json and echo the json result.

 

In your javascript function, you would parse the json object (I think jquery has a parse function) and use that javascript object in the function.

[fishbaitfood]

Hey,

 

Thanks for the tip!

But could you please give me a clear example of the javascript workaround using json and a parse function?

Can't find it for use in my context.

 

EDIT: I think I've found something! Again, thanks for the tip!