Only one select list works on PHP form

kristo5747 · August 24, 2011

**Disclaimer: It's been a while since I last wrote any code. The quality of my code is likely to be sub-par. You've been warned.**

I have a basic form that's meant to search flat files on our server. The "search engine" I created as two select lists: one for the file names and one for the customer site files come from.

For a reason I can't figure out, whatever option I select from the second select list is never captured when I hit Submit.

However, whatever option I select from the first select list is always captured.

What am I missing? I am sure it's starting right at me.... Any hints welcome. Thank you.

Here's my code:

<HTML>
    <head><title>SEARCH TOOL - PROTOTYPE</title></head>
    <body><h1>SEARCH TOOL - PROTOTYPE</h1>
    <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
    <fieldset>
    <legend>Filename (one item)</legend><select name="DBFilename" id="DBFilename" size="0">
    <?php $con = mysql_connect("localhost",  "user", "pass"); if (!$con) {  die('Could not connect: ' . mysql_error());}
    mysql_select_db("dev", $con) or die(mysql_error());
    $result = mysql_query("select distinct filename from search_test");
    while ($row = mysql_fetch_array($result))
    { ?>    <option value="<?php echo $row['filename']; ?>"><?php echo $row['filename']; ?></option> <?php } mysql_close($con); ?>
    </select></fieldset>
    <fieldset>
    <legend>Site (one item)</legend><select name="DBSite" id="DBSite">
    <?php $con = mysql_connect("localhost",  "user", "pass"); if (!$con) {    die('Could not connect: ' . mysql_error());}
    mysql_select_db("dev", $con) or die(mysql_error());
    $result = mysql_query("select distinct site from search_test");
    while ($row = mysql_fetch_array($result))
    { ?>        <option value="<?php echo $row['site']; ?>"><?php echo $row['site']; ?></option> <?php } mysql_close($con);
    ?>
    </select></fieldset>
    <input type="submit" name="submit" value="submit" >
    <input type="button" value="Reset Form" onClick="this.form.reset();return false;" />
    </form>
    </body>
    </HTML>
    <?php
    
    if (isset($_POST['submit'])) {
    
            if (!empty($_POST['DBFilename'])) {doFileSearch();}
                    elseif (!empty($_POST['DBSite'])) {doSite();}
    }
    
    function doFileSearch() {
    $mydir = $_SERVER['DOCUMENT_ROOT'] . "/filedepot";
    $dir = opendir($mydir);
    $DBFilename = $_POST['DBFilename'];
    
    $con = mysql_connect("localhost", "user", "pass");
    if (!$con) {die('Could not connect: ' . mysql_error());}
    mysql_select_db("dev", $con) or die("Couldn't select the database.");
    
    $getfilename = mysql_query("select filename from search_test where filename='" . $DBFilename . "'") or die(mysql_error());
    
    echo "<table><tbody><tr><td>Results.</td></tr>";
    while ($row = mysql_fetch_array($getfilename)) {
                    $filename = $row['filename'];
                    echo '<tr><td><a href="' . basename($mydir) . '/' . $filename . '"  target="_blank">' . $filename . '</a></td></tr>';
            }
                    echo "</table></body>";
    }
    
    function doSite() {
    $mydir = $_SERVER['DOCUMENT_ROOT'] . "/filedepot";
    $dir = opendir($mydir);
    $DBSite = $_POST['DBSite'];
    
    $con = mysql_connect("localhost", "user", "pass");
    if (!$con) {die('Could not connect: ' . mysql_error());}
    mysql_select_db("dev", $con) or die("Couldn't select the database.");
    
    $getfilename = mysql_query("select distinct filename from search_test where site='" . $DBSite . "'") or die(mysql_error());
    
    echo "<table><tbody><tr><td>Results.</td></tr>";
    while ($row = mysql_fetch_array($getfilename)) {
                    $filename = $row['filename'];
                    echo '<tr><td><a href="' . basename($mydir) . '/' . $filename . '"  target="_blank">' . $filename . '</a></td></tr>';
            }
                    echo "</table></body>";
    
    }
    ?>

kristo5747 · August 24, 2011

Added the source of what is created to a pastebin: http://pastebin.com/raw.php?i=mjxkVEmW

WebStyles · August 24, 2011

Are you sure about this???

select filename from search_test where filename='".$DBFilename."'

you're selecting filename where filename equals the filename you already have. Kind of redundant.

kristo5747 · August 24, 2011

Are you sure about this???
select filename from search_test where filename='".$DBFilename."'
you're selecting filename where filename equals the filename you already have. Kind of redundant.

I am sure there better ways to do that...all I want to do is provide a URL to the file located on the server for the file selected from the list.

If you have better suggestion, I am all ears.

WebStyles · August 24, 2011

can you post the list of fields you have in table `search_test` please ?

kristo5747 · August 24, 2011

filename 	site 	script 	station 	result 	stbmodel 	rid 	testdate

WebStyles · August 24, 2011

I sort of re-wrote your code, created a function to handle mysql connection, and put functions nice and tidy at top of page.

However, I cannot test this code because I don't have the database here.

try this:

<?php
// functions
function con(){
    $c = mysql_connect("localhost",  "user", "pass") or die('Could not connect: ' . mysql_error());
    mysql_select_db("dev", $con) or die(mysql_error());
    return $c;
}
function doSite($DBSite) {
    $mydir = $_SERVER['DOCUMENT_ROOT'] . "/filedepot";
    $dir = opendir($mydir);
    $con = con();
    $getfilename = mysql_query("select distinct `filename` from `search_test` where `site`='$DBSite'",$con) or die(mysql_error());
    $result = '<table><tr><td>Results.</td></tr>';
    while ($row = mysql_fetch_array($getfilename)){
        $result .= '<tr><td><a href="' . basename($mydir) . '/' . $row['filename'] . '"  target="_blank">' . $row['filename'] . '</a></td></tr>';
    }
    @mysql_close($con);
    $result .= '</table>';
return $result;    
}
function doFileSearch($DBFilename) {
    $mydir = $_SERVER['DOCUMENT_ROOT'] . "/filedepot";
    $dir = opendir($mydir);
    $con = con();
    $getfilename = mysql_query("select `filename` from `search_test` where `filename`='$DBFilename'",$con) or die(mysql_error());
    
    $result = '<table><tr><td>Results.</td></tr>';
    while ($row = mysql_fetch_array($getfilename)) {
         $result .= '<tr><td><a href="' . basename($mydir) . '/' . $row['filename'] . '"  target="_blank">' . $row['filename'] . '</a></td></tr>';
    }
    @mysql_close($con);
    $result .= '</table>';
}
?>
<HTML>
    <head><title>SEARCH TOOL - PROTOTYPE</title></head>
    <body><h1>SEARCH TOOL - PROTOTYPE</h1>
    <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
    <fieldset>
    <legend>Filename (one item)</legend><select name="DBFilename" id="DBFilename" size="1">
    <?php
    $con = con();
    $result = mysql_query("select distinct `filename` from `search_test` order by `filename`",$con);
    while ($row = mysql_fetch_array($result)){
    	echo '<option value="'.$row['filename'].'">'.$row['filename'].'</option>';
    }
    @mysql_close($con);
    ?>
    </select></fieldset>
    <fieldset>
    <legend>Site (one item)</legend><select name="DBSite" id="DBSite" size="1">
    <?php
    $con = con();
    $result = mysql_query("select distinct `site` from `search_test` order by `site`",$con);
    while ($row = mysql_fetch_array($result)){
    	echo '<option value="'.$row['site'].'">'.$row['site'].'</option>';
    }
    @mysql_close($con);
    ?>
    </select></fieldset>
    <input type="submit" name="submit" value="submit" >
    <input type="button" value="Reset Form" onClick="this.form.reset();return false;" />
    </form><br /><br />
    <?php
    if (isset($_POST['submit'])){
            if (!empty($_POST['DBFilename'])){
            	echo doFileSearch($_POST['DBFilename']);
            }
            echo '<br /><br />';
            if(!empty($_POST['DBSite'])){
            	echo doSite($_POST['DBSite']);
            }
    }
    ?>
    </body></html>

turn on errors, 'cause there's bound to be a typo somewhere in there, as it is all untested

kristo5747 · August 24, 2011

I sort of re-wrote your code, created a function to handle mysql connection, and put functions nice and tidy at top of page.

However, I cannot test this code because I don't have the database here.

try this:
<?php
...............

I tried your code but to no avail. The first SELECT works fine. The second SELECT is never submitted.

WebStyles · August 24, 2011

can you do a dump of your table in .sql format so I can set it up here?

kristo5747 · August 24, 2011

Ignore my previous posts. I did not fix all typos. It's working now.Thank you!!

It's working now but it seemingly introduced a new problem: I can't seem to do more than one search at a time. The result shows up again and again. I am using Firefox 6.0 on Ubuntu.

kristo5747 · August 25, 2011

Complete re-write here => http://pastebin.com/raw.php?i=qi5F7X2e

There are several problems with my form.

a) Neither one of my SELECT lists are ever empty.

b) I never check for return the values from my functions.

This one is working.

Thanks for taking the time.

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Only one select list works on PHP form

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