How to make a search with many options

[feri_soft]

By the way its form now i get an error again:

[code]if(!empty($district)){
$district = join ("','", $district);
$where[] = "(district IN ('$district'))";
}[/code]

when i view the output its not in('1','2'.....)
but 1','2 ... and i get Column 'district' in where clause is ambiguous

Help please

[Barand]

If you view $district you will get 1','2

If it says district is ambiguous then you must be selecting the same column name from more than one table, maybe because you are using "SELECT * FROM). Specify which one to use eg

$where[] = "(listings.district IN ('$district'))";