ploppy Posted September 16, 2011 Share Posted September 16, 2011 hello. I seemed to have got lost with my if statements here and cannot see where to use elseif . I am getting the duplicate response message ok, but if I submit with blank input, it produces NaN error, which I know is JavaScript but I think it is because of the order of the if statements. If someone could help me with this I would be very grateful. Thanks. if (!empty ($_POST['item'])) { $data = split(',',$_POST['item'][0]); $duplicates = array(); foreach ($data as $val) { if ( $val != "" ) { $sql = "SELECT custref FROM boxes WHERE custref='$val' Union SELECT item FROM act WHERE item='$val'"; $qry = mysql_query($sql) or die(mysql_error()); if(mysql_num_rows($qry)) { $duplicates[] = $val; } } } if(count($duplicates)) { $response_array['status'] = 'error'; $response_array['message'] = 'No duplicate files'; } } //check the name field elseif(empty($authorised)){ //set the response $response_array['status'] = 'error'; $response_array['message'] = 'Name cannot be blank'; //check the service field } Link to comment https://forums.phpfreaks.com/topic/247260-nested-if-statements-causing-error/ Share on other sites More sharing options...
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