Get names from foreach and insert them in the db

[Kleidi]

Hello,

I have a simple image multi uploader that uploads images on the folder correctly but i don't know how to get the image names and insert them in the db. The uploader is part of a complex form for adding an article informations (id, name, permanenturl, section, etc) that works correctly.

Image fields in db has names as follows: img1 img2 img3 img4 im5, a field for each image (since i thought that this is the best way to add the images on the article).

The upload sections looks like this:

<?php

/**

* Smart Image Uploader by @cafewebmaster.com

* Free for private use

* Please support us with donations or backlink

*/





$upload_image_limit = 5; // How many images you want to upload at once?

$upload_dir	= "/var/www/tour/te-ngarkuara/oferta/"; // default script location, use relative or absolute path

################################# UPLOAD IMAGES

	foreach($_FILES as $k => $v){ 

		$img_type = "";

		### $htmo .= "$k => $v<hr />"; 	### print_r($_FILES);

		if( !$_FILES[$k]['error'] && preg_match("#^image/#i", $_FILES[$k]['type']) && $_FILES[$k]['size'] < 1000000){

			$img_type = ($_FILES[$k]['type'] == "image/jpeg") ? ".jpg" : $img_type ;

			$img_type = ($_FILES[$k]['type'] == "image/gif") ? ".gif" : $img_type ;

			$img_type = ($_FILES[$k]['type'] == "image/png") ? ".png" : $img_type ;

			$data = (date("jnHi")); // Merr daten dhe oren ne momentin e shtimit te fotografise

			$img_rname = $data."-".$_FILES[$k]['name']; // shton daten dhe oren perpara emrit te fotografise per te krijuar emer unik
			$img_rname = str_replace(" ","-",$img_rname); // Heq hapesirat dhe i zevendeso me -

			$img_path = $upload_dir.$img_rname;

			copy( $_FILES[$k]['tmp_name'], $img_path );
			chmod("$img_path",0777); 

			$feedback .= "Image and thumbnail created $img_rname<br />";

		}

	}



############################### HTML FORM

while($i++ < $upload_image_limit){

	$form_img .= '<label>Image '.$i.': </label> <input type="file" name="uplimg'.$i.'"><br />';

}



$htmo .= '

	<p>'.$feedback.'</p>

	<form method="post" enctype="multipart/form-data">

		'.$form_img.' <br />

		<input type="submit" value="Upload Images!" style="margin-left: 50px;" />

	</form>

	';	



echo $htmo;

Can anyone help me on this, please?

 

Thank you in advance!