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$_POST Problems


AltarofScience

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I have a code designed to build buildings on space colonies.

The problem is that once you click the form button, the building is built, but you need to reload the page before it will show the updated count.

Is there a way to refresh a page so that the change shows up without the user doing anything?

 

<?php
$dbhost = 'localhost:3306';
$dbuser = 'root';
$dbpass = 'root';
$dbname = 'aosdb';
$conn = mysql_connect($dbhost,$dbuser,$dbpass)
or die ('Error connecting to mysql');
mysql_select_db($dbname);
$query="SELECT * FROM IMPrints";
$result=mysql_query($query);
$name = mysql_result($result, 0, 'name');
$work = mysql_result($result, 0, 'workers');
$effi = mysql_result($result, 0, 'efficiency');
$cost = mysql_result($result, 0, 'cost');
$iron = mysql_result($result, 0, 'iron');
$copp = mysql_result($result, 0, 'copper');
$silv = mysql_result($result, 0, 'silver');
$titan = mysql_result($result, 0, 'titanium');
$gold = mysql_result($result, 0, 'gold');
$uran = mysql_result($result, 0, 'uranium');
$plat = mysql_result($result, 0, 'platinum');
$diam = mysql_result($result, 0, 'diamonds');
$oil = mysql_result($result, 0, 'oil');
$water = mysql_result($result, 0, 'water');
?>
<div class="building">
<p class="bd" id="name">| Name: <?php echo $name ?></p>
<p class="bd" id="workers">| Staff: <?php echo $work ?></p>
<p class="bd" id="efficiency">| Effic: <?php echo $effi ?></p>
<p class="bd" id="cost">| Cost: <?php echo $cost ?></p>
<p class="bd" id="iron">| Ir: <?php echo $iron ?></p>
<p class="bd" id="copper">| Cop: <?php echo $copp ?></p>
<p class="bd" id="silver">| Silv: <?php echo $silv ?></p>
<p class="bd" id="titanium">| Titan: <?php echo $titan ?></p>
<p class="bd" id="gold">| Gol:<?php echo $gold ?></p>
<p class="bd" id="uranium">| Uran: <?php echo $uran ?></p>
<p class="bd" id="platinum">| Plat: <?php echo $plat ?></p>
<p class="bd" id="diamonds">| Diam: <?php echo $diam ?></p>
<p class="bd" id="oil">| Oi: <?php echo $oil ?></p>
<p class="bd" id="water">| Wat: <?php echo $water ?></p>
<?php 
$dbhost = 'localhost:3306';
$dbuser = 'root';
$dbpass = 'root';
$dbname = 'aosdb';
$conn = mysql_connect($dbhost,$dbuser,$dbpass)
or die ('Error connecting to mysql');
mysql_select_db($dbname);
$queryp = "SELECT Basic FROM IMBuilt WHERE idcol = $idcol";
$resultp = mysql_query($queryp);
$Basic = mysql_result($resultp, 0);
if(isset($_POST['built'])) {
if($_POST) {
$Badd = $Basic+$_POST['built'];
$queryi="UPDATE IMBuilt SET Basic=$Badd WHERE idcol = $idcol";
mysql_query($queryi);
}
}
?>
<p class="bd" id="built">| Built: <?php echo $Basic ?> |</p>
<form class="bd" method="post" action="IronMineList.php"><input type="varchar" name="built"><input type="submit" value="Build"></form>
</div>

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You need to put the logic that displays the data AFTER the logic that updates the data.

 

You also need to use just one set of code that makes a connection to the database server and mysql_result is the slowest way of accessing data from a query. You should just use one mysql_fetch_assoc statement to fetch the whole row at one time instead of a number of mysql_result statements.

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https://forums.phpfreaks.com/topic/247791-_post-problems/#findComment-1272445
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Okay, I got it:

<?php 
$dbhost = 'localhost:3306';
$dbuser = 'root';
$dbpass = 'root';
$dbname = 'aosdb';
$conn = mysql_connect($dbhost,$dbuser,$dbpass)
or die ('Error connecting to mysql');
mysql_select_db($dbname);
$queryp = "SELECT Basic FROM IMBuilt WHERE idcol = $idcol";
$resultp = mysql_query($queryp);
$Base = mysql_result($resultp, 0);
if(isset($_POST['built'])) {
if($_POST) {
$Badd = $Base+$_POST['built'];
$queryi="UPDATE IMBuilt SET Basic=$Badd WHERE idcol = $idcol";
mysql_query($queryi);
}
}
$queryf = "SELECT Basic FROM IMBuilt WHERE idcol = $idcol";
$resultf = mysql_query($queryf);
$Basic = mysql_result($resultf, 0);
?>

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https://forums.phpfreaks.com/topic/247791-_post-problems/#findComment-1272449
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