echoing check box

[droidus]

how do i echo "checked=checked" for a checkbox?  here is what i have:

 

<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' if($IPCheck == true) {/"checked=checked/" } />

 

this code will be echoed!

[codefossa]

<input type="checkbox" name="ip_automatic_login" id="ip_automatic_login" value="1" <?php if ($IPCheck) { ?> checked="1" <?php } ?> />

or

 

$checked = $IPCheck ? 1 : 0;

echo '<input type="checkbox" name="ip_automatic_login" id="ip_automatic_login" value="1" checked="' . $checked . '" />';

Either should work fine.

[Psycho]

@Kira,

 

The proper way to check a checkbox is with checked="checked"

 

$checked = ($IPCheck) ? "checked='checked' "; : '';
echo "<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' {$checked}/>";

 

[xyph]

@Kira,

 

The proper way to check a checkbox is with checked="checked"

 

$checked = ($IPCheck) ? "checked='checked' "; : '';
echo "<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' {$checked}/>";

 

 

checked

When the type attribute has the value "radio" or "checkbox", this boolean attribute specifies that the button is on. User agents must ignore this attribute for other control types.

 

http://www.w3.org/TR/html4/interact/forms.html#adef-checked

 

Funny, how it says 'that that button is on' and not 'if the button is on' though it's a boolean attribute. Leads to a little confusion.

 

But you are correct.

[droidus]

@Kira,

 

The proper way to check a checkbox is with checked="checked"

 

$checked = ($IPCheck) ? "checked='checked' "; : '';
echo "<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' {$checked}/>";

 

i am using an echo statement though, so i had to change the code around:

 

echo " $checked = ($IPCheck) ? \"checked='checked' \"; : '';
echo \"<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' {$checked}/>\"; ";

 

all i get though, is this:

 

? = (1) ? "checked='checked' "; : ''; echo ""; 

[Buddski]

You are echoing the ternary operator, that is why you are getting that output..

If you are already in an echo statement when trying to add the checked you can do this, but what mjdamato said was correct, if left unmodified.

echo "<input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' ".($IPCheck == true ? "checked=checked" : "")." />";

[droidus]

oh, ok, it does work.  sorry