PHP date

[gary00ie]

Hi,

 

I need a fast function to extract the year (YYYY) from a string.

 

The string will be YYYY-MM-DD or DD-MM-YYYY.

Would a regular expression help with this?  Maybe something like:

echo preg_match($dateStr);

 

Any help would be appreciated.  I'm getting nowhere with this.

Thanks in advance

[smerny]

preg_match('/\d{4}/', $dateStr, $matches);

 

will put every match of a 4 digit number in an array $matches

[AyKay47]

if those are the only characters in the string.. you can use this simple pattern for your preg_match..

 

$pattern = "~\d{4}~";

 

Edit: above poster beat me to it...

[gary00ie]

Thank you both for the replies.

 

So could I have - as the delimiter also?

$dateStr = '2010/11/11';  // or 2010-11-11 
echo preg_match('/\d{4}/', $dateStr, $matches);

Also, $dateStr could also be: DD-MM-YYYY also, correct?

[cunoodle2]

There may be a way to do this with a regular expression but I have no clue how to do that so I would do something like this..

 

<?php

//this case would be MM-DD-YYYY
if ((strpos($dateStr, "-") == 2) && (strrpos($dateStr, "-") == 5)
     //then strip off the last 4 characters

//this case would be YYYY-MM-DD
else if ((strpos($dateStr, "-") == 4) && (strrpos($dateStr, "-") == 7)
     //then strip off the first 4 characters

?>

 

would this work?

[xyph]

Thank you both for the replies.

 

So could I have - as the delimiter also?

$dateStr = '2010/11/11';  // or 2010-11-11 
echo preg_match('/\d{4}/', $dateStr, $matches);

Also, $dateStr could also be: DD-MM-YYYY also, correct?

 

All of those are correct.