ryanfilard Posted October 21, 2011 Share Posted October 21, 2011 What is wrong? Warning: mysql_select_db(): supplied resource is not a valid MySQL-Link resource in /home/rweekly/public_html/2012/view_arguments.php on line 41 Warning: mysql_query(): supplied resource is not a valid MySQL-Link resource in /home/rweekly/public_html/2012/view_arguments.php on line 43 mysql_select_db($database_news, $news); $query_news = "SELECT * FROM news WHERE id = '$id'"; $news = mysql_query($query_news, $news) or die(mysql_error()); $row_news = mysql_fetch_assoc($news); $totalRows_news = mysql_num_rows($news); mysql_select_db($database_news, $news); $query_arguments = "SELECT * FROM argue WHERE pid = '$id'"; $arguments = mysql_query($query_arguments, $news) or die(mysql_error()); $row_arguments = mysql_fetch_assoc($arguments); $totalRows_arguments = mysql_num_rows($arguments); Link to comment https://forums.phpfreaks.com/topic/249500-mysql-link-not-valid/ Share on other sites More sharing options...
PFMaBiSmAd Posted October 21, 2011 Share Posted October 21, 2011 $news is not a valid MySQL-Link resource and you would need to troubleshoot why it is not. It's either not getting set at all or it is not getting set to the result of a mysql_connect() statement. I would recommend using a better name for a database connection variable than $news. It's fairly likely that you are using $news for some other purpose in your script and the connection resource got overwritten. Link to comment https://forums.phpfreaks.com/topic/249500-mysql-link-not-valid/#findComment-1281011 Share on other sites More sharing options...
ryanfilard Posted October 21, 2011 Author Share Posted October 21, 2011 this is all of my php code <?php require_once('Connections/news.php'); ?> <?php $id = $_REQUEST['id']; if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } mysql_select_db($database_news, $news); $query_news = "SELECT * FROM news WHERE id = '$id'"; $news = mysql_query($query_news, $news) or die(mysql_error()); $row_news = mysql_fetch_assoc($news); $totalRows_news = mysql_num_rows($news); mysql_select_db($database_news, $news); $query_arguments = "SELECT * FROM argue WHERE pid = '$id'"; $arguments = mysql_query($query_arguments, $news) or die(mysql_error()); $row_arguments = mysql_fetch_assoc($arguments); $totalRows_arguments = mysql_num_rows($arguments); ?> Link to comment https://forums.phpfreaks.com/topic/249500-mysql-link-not-valid/#findComment-1281017 Share on other sites More sharing options...
ryanfilard Posted October 21, 2011 Author Share Posted October 21, 2011 I found it $news was in the required file. But I still get this Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/rweekly/public_html/2012/view_arguments.php on line 37 Link to comment https://forums.phpfreaks.com/topic/249500-mysql-link-not-valid/#findComment-1281018 Share on other sites More sharing options...
PFMaBiSmAd Posted October 21, 2011 Share Posted October 21, 2011 Someone already guessed what is causing the problem - I would recommend using a better name for a database connection variable than $news. It's fairly likely that you are using $news for some other purpose in your script and the connection resource got overwritten. You are using $news to hold the result from a mysql_query() statement. It is no longer the connection resource after that point in your code. The names you use for variables should indicate the purpose of that variable. As already stated, $news is not a good name for a mysql connection. Link to comment https://forums.phpfreaks.com/topic/249500-mysql-link-not-valid/#findComment-1281023 Share on other sites More sharing options...
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