Giving an ID to a form?

[Pain]

Hello everyone.

 

I am wondering how can i give different id's to a html form?

 

<?php
...
if ($numrows!=0)
{
// fetching data from the database to variable
while ($row = mysql_fetch_assoc($query))
{
	$view_jam = $row['jamname'];
	$view_recipe = $row['jamrecipe'];
	$view_rating = $row['jamrate'];
	$view_owner = $row['owner'];
	$view_comments = $row['comments'];
	$view_count = $row['count'];
	$view_id = $row['id'];
	$view_count2 = $row['count2'];



	echo "Jam name: <b>" . $view_jam . "</b><br />";
	echo "Jam recipe: " . $view_recipe . "<br />";
	echo "Owner: " . $view_owner . "<br />";
	echo "Comments: " . $view_comments . "<br />";
	echo "Jam Rating: " . $view_rating . "<br />";
	[b]echo '<form action="main.php?id=jams" method="POST">[/b]
Choose rating 
<input type="text" name="jamrate" />

<input type="submit" name="submit1" value="Rate">
</form><br /><br />'; 		
...
?>

As you can see, the form is inside a loop.

I am trying to build a rating system. When there is only one row in a database then everything goes smoothly, but if there are more, then the rating applies to all rows.

I suppose i need to give different id's to the form. How?

 

Thank you

[AyKay47]

why do you have the entire form inside of the while loop? instead, if anything, have the form outside of the while loop and have the inputs generated in the while loop if the correct conditions are met.

[Pain]

User can upload thing, so when they do that i need a rating form to appears instantly. That's why it is inside the loop.

[redarrow]

use a input and give it a id.

<?php

$id="example";

?>

<input type="text" name="id" value="<?php echo $id; ?>">

 

Get me.

 

<?php


if($_POST['id']=="example"){

echo "cheers mate good idea";

}else{

echo"Bad idea";

}
?>

[xyph]

If you use the above example, but change the type to 'hidden', the value will be carried to the action page without being directly visible to the end user.

[Pain]

No, thats not working, besides my form is already has name "jamrate". The problem is that when the loop goes on, my form's name remains "submit1". And i have this code:

<?php
...
if($submit1)
{
$counted = $view_count + 1;
$myQuery = "UPDATE jam SET count = '$counted' WHERE id = '$view_id'";
mysql_query($myQuery);

$counted3 = $view_count2 + $rating_post;
$myQuery1 = "UPDATE jam SET count2 = '$counted3' WHERE id = '$view_id'";
mysql_query($myQuery1);

$finalrating = $counted3/$counted;
$myQuery2 = "UPDATE jam SET jamrate = '$finalrating' WHERE id = '$view_id'";
mysql_query($myQuery2);
$finalquery = mysql_query("SELECT * FROM jam");
$numrows1 = mysql_num_rows($finalquery);
        ...
        ?>        

 

And this is my loop

<?php
...
while ($row = mysql_fetch_assoc($query))
{
	$view_count = $row['count'];
	$view_id = $row['id'];
	$view_count2 = $row['count2'];

                echo "Comments: " . $view_comments . "<br />";
	echo "Jam Rating: " . $view_rating . "<br />";
	echo '<form action="main.php?id=jams" method="POST">
Choose rating 
<input type="hidden" name="jamrate" />
<select name="jamrate">
<option>1</option>
<option>2</option>
<option>3</option>
<option>4</option>
<option>5</option>
</select>

<input type="submit" name="submit1" value="Rate">
</form><br /><br />'; 		
...
?>

 

So everytime a new loop starts, my form will update all rows, because the name remains "submit1", but i need to update only one, therefore id's or name's should be different each time.

 

 

 

 

[Pain]

Sorry, my submit button is submit1, not my form. So now im confused, do i have to give different names (or id's) to the form or to the actual submit button?

[AyKay47]

to figure out which form has been submitted? you can do this by have unique submit button names, then check to see which one has been clicked using $_POST['submit_name']

[Pain]

I need each button to get a name automatically.

[Pain]

I fixed it.