shebbycs Posted November 9, 2011 Share Posted November 9, 2011 My database name is cute and in cute database contain chatmessages and ipbans tables in which chatmessages contains id(auto increment), name, IP,postime and message and here is the form2.php coding form 2.php <?php mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("cute") or die(mysql_error()); $message=$_POST['message']; $n=$_POST['username']; $name=$_POST['name']; if(isset($_POST['submit'])) //if submit button push has been detected { if(strlen($message)>1) { $message=strip_tags($message); $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP $checkforbanned="SELECT IP from ipbans where IP='$IP'"; $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS"); if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list { print "You IP is banned from posting."; } else { $thedate = date("U"); //grab date and time of the post $insertmessage="INSERT into chatmessages (name,IP,postime,message) values('$name','$IP','$thedate','$message')"; mysql_query($insertmessage) or die("Could not insert message"); } } } ?> <html> <head> <script type="text/javascript"> function addsmiley(code) { var pretext = document.smile.message.value; this.code = code; document.smile.message.value = pretext + code; } function a() { var x = document.smile.message.value; if(x=="") { alert("Please insert an message!"); return false; } } </script> <style type="text/css"> body{ background-color: #d8da3d } </style> </head> <body> <form name="smile" method="post" action="form2.php" onSubmit="return a()" > Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br> <img src="smile.gif" alt="" onClick="addsmiley('')" style="cursor:pointer;border:0" /> <img src="blush.gif" alt="" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" /> <input type="hidden" name="name" value="<?php echo $n;?>"> <input type='submit' name='submit' value='Set Name' class='biasa' ></form> <br> <br> </body> </html> my problem is if the first chat message that i click submit button it would be appear name:message but when the second time submit it only appear the message but the name is blank(nothing and empty) This is my login.php <?php mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("Regis") or die(mysql_error()); if (isset($_POST["sub"])) { $_POST['pass'] = md5($_POST['pass']); if (!get_magic_quotes_gpc()) { $_POST['username'] = addslashes($_POST['username']); $_POST['pass'] = addslashes($_POST['pass']); } $usercheck = $_POST["username"]; $check = mysql_query("SELECT username FROM registration WHERE username = '$usercheck'") or die(mysql_error()); $check2 = mysql_num_rows($check); //if the name exists it gives an error if ($check2 != 0) { echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('Sorry, the username" ." ".$usercheck." ". "is already in use.')</SCRIPT>"); echo ("<SCRIPT LANGUAGE='JavaScript'>setTimeOut(window.location = 'registration.php',1)</script>"); } else if($_POST['username'] && $_POST['pass'] && $_POST['pass2'] ) { $insert = "INSERT INTO registration (username, password) VALUES ('".$_POST['username']."', '".$_POST['pass']."')"; $add_member = mysql_query($insert); echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('Registration had been succesfully added ')</SCRIPT>"); } } ?> <html> <head> <script type="text/javascript"> function a() { var x = document.login.username.value; var y = document.login.pass.value; if(x==""&& y=="") { alert("Please insert all message!"); return false; } if(x=="") { alert("Please insert an username!"); return false; } if(y=="") { alert("Please insert an password!"); return false; } } </script> </head> <body> <table border="0"> <form name="login" method="post" action="form2.php" onsubmit="return a()"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>Username:</td> <td><input type="text" name="username" maxlength="40"></td></tr> <tr><td>Password:</td> <td><input type="password" name="pass" maxlength="50"></td></tr> <tr><td><input type="submit" name="submit" value="Register"></a></td> <td><input type="submit" name="submit" value="Login"></td></tr> </form> </body></html> So how to make when the second and next submit click button, it would appear name with message ? Quote Link to comment https://forums.phpfreaks.com/topic/250782-the-name-is-not-appear-after-the-second-time-submit-for-the-chat/ Share on other sites More sharing options...
shebbycs Posted November 9, 2011 Author Share Posted November 9, 2011 sorry again im had found solution myself i had fixed it <?php mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("cute") or die(mysql_error()); $message=$_POST['message']; $n=$_POST['username']; if(isset($_POST['submit'])) //if submit button push has been detected { if(strlen($message)>1) { $message=strip_tags($message); $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP $checkforbanned="SELECT IP from ipbans where IP='$IP'"; $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS"); if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list { print "You IP is banned from posting."; } else { $thedate = date("U"); //grab date and time of the post $insertmessage="INSERT into chatmessages (name,IP,postime,message) values('$n','$IP','$thedate','$message')"; mysql_query($insertmessage) or die("Could not insert message"); } } } ?> <html> <head> <script type="text/javascript"> function addsmiley(code) { var pretext = document.smile.message.value; this.code = code; document.smile.message.value = pretext + code; } function a() { var x = document.smile.message.value; if(x=="") { alert("Please insert an message!"); return false; } } </script> <style type="text/css"> body{ background-color: #d8da3d } </style> </head> <body> <form name="smile" method="post" action="form2.php" onSubmit="return a()" > Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br> <img src="smile.gif" alt="" onClick="addsmiley('')" style="cursor:pointer;border:0" /> <img src="blush.gif" alt="" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" /> <input type="hidden" name="username" value="<?php echo $n;?>"> // <input type="hidden" name="nama" value="<?php echo $name;?>"> <input type='submit' name='submit' value='Set Name' class='biasa' ></form> <br> <br> </body> </html> problem solved thanks you Quote Link to comment https://forums.phpfreaks.com/topic/250782-the-name-is-not-appear-after-the-second-time-submit-for-the-chat/#findComment-1286685 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.