Passing arguments into another function

[x1nick]

I have a odd one here, two classes and one which calls another class.

I want to pass all of the parameters from the array as seperate variables into the next function. Hope my example explains a little better

 

class master

{

  public function __call($name, $args)

  {

    second->$name($args);

  }

}

 

class second

{

  public function example($param1, $param2)

  {

 

  }

}

 

master->example($param1, $param2);

 

( i know its not accurate php, but should get the idea of what im trying to do)

I need to do something with the following line

second->$name($args);

Where param1 and param2 will be seperated out

Is there a php function which you can tell it the class, method name and pass it an array of parameters?

 

Thanks

[x1nick]

Answred my own question

http://php.net/manual/en/function.call-user-func-array.php

 

Oops might help someone else anyway!

[Drongo_III]

I have a odd one here, two classes and one which calls another class.

I want to pass all of the parameters from the array as seperate variables into the next function. Hope my example explains a little better

 

class master

{

  public function __call($name, $args)

  {

    second->$name($args);

  }

}

 

class second

{

  public function example($param1, $param2)

  {

 

  }

}

 

master->example($param1, $param2);

 

( i know its not accurate php, but should get the idea of what im trying to do)

I need to do something with the following line

second->$name($args);

Where param1 and param2 will be seperated out

Is there a php function which you can tell it the class, method name and pass it an array of parameters?

 

Thanks

 

 

Can't you just use

 class second extends master 

Then you should be able to access everything from the master class in the second class.

Or maybe i've misunderstood you :/