spike-spiegel Posted December 2, 2011 Share Posted December 2, 2011 Well, the page is not displaying the sql results, perhaps there is something wrong in this line, but I still dont know how to fix: echo "<tr bgcolor=\"$col\"><td><a class=TN href=\"javascript:popUp('preview.php?uname=$a1[uname]&ename=$ename')\"> $a2[0] $a2[1]</a></td><td> $a1[clname] </td></tr>"; Is it the $a2[0] $a2[1] part? The code: { $q2 = "select fname, lname from job_seeker_info where uname = \"$a1[uname]\" "; $r2 = mysql_query($q2) or die(mysql_error()); $a2 = mysql_fetch_array($r2); if($col == "cococo") { $col = "dddddd"; } else { $col = "cococo"; } echo "<tr bgcolor=\"$col\"><td><a class=TN href=\"javascript:popUp('preview.php?uname=$a1[uname]&ename=$ename')\"> $a2[0] $a2[1]</a></td><td> $a1[clname] </td></tr>"; } If you want the full code, let me know. Quote Link to comment https://forums.phpfreaks.com/topic/252350-sql-wont-display-results/ Share on other sites More sharing options...
ebruggema Posted December 13, 2011 Share Posted December 13, 2011 You can add print_r($a2) to your script (after the fetch) and you'll see what the content of $a2 is! Quote Link to comment https://forums.phpfreaks.com/topic/252350-sql-wont-display-results/#findComment-1297390 Share on other sites More sharing options...
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