How to Match a Part Number

[imperium2335]

Hi,

 

How would I write a regex that would match words that have a mixture of numbers, letters and symbols but no spaces. e.g.:

 

"I would like 1 LG1K065Q704"

[OOP]

Hi there

You can use this

 

"^[a-zA-Z0-9]*$"

 

[imperium2335]

Thanks, but it didn't work That goes ahead and matches most things.

 

I tried /[a-z][A-Z][0-9]/i which seems to work but since I did it I don't think it will be that reliable, what do you think?

[OOP]

The regex I have provided above will match any alphanumeric? This is what you want, right?

 

change it to this and it will not accept empty string

 

"^[a-zA-Z0-9]+$"

[imperium2335]

But I only want it to match the product code LG1K065Q704, and no other word in the paragraph.

 

In pseudo: match a word that MUST have numbers and letters and/or symbols and no spaces in it.

[OOP]

Okay,

Is your product code random? or does it have to start with character? can you specify the format you want to validate?

[imperium2335]

product codes could be anything, usually greater than 4 characters long. This is for something that will find part codes in emails from clients, so they could be like this:

 

"I want 1 123-abc-ppr5"

or

"55-33-AB/8 x5"

[xyph]

<?php 

$expr = '/(?:^| )((?:[0-9]+[a-z]|[a-z]+[0-9])[a-z0-9]+)/si';
$str = 'hahaha ae232a4d zomg wut wut wut asgfe 3231aa3dw';

preg_match_all( $expr, $str , $matches, PREG_PATTERN_ORDER );

header( 'Content-type: text/plain' ); // display in plain text
print_r( $matches[1] );

?>

 

returns

 

Array
(
    [0] => ae232asd
    [1] => 3231aadw
)

 

It's slightly faster than positive look-ahead.

 

It first searches for a space, or the start the string/new line

It then checks for either letters followed by a number, or numbers followed by a letter

It then captures the remaining letters or numbers

[imperium2335]

What does the 's' do in the /si part?

 

If I put this into my javascript it gives a syntax error:

 

var partTest = /(?:^| )((?:[0-9]+[a-z]|[a-z]+[0-9])[a-z0-9]+)/si ;

 

if I drop the 's' it works.

[Winstons]

What does the 's' do in the /si part?

Modificator 's' - ignoring chars of new line "\r\n" or "\n".

Modificator 'i' - ignoring the case of letters.

JavaScript haven't the modifocator 's', instead of this use modif. 'g'

Try this

var partTest = /(?:^| )((?:\d+[a-z]|[a-z]+\d)[a-z\d]+)/gi;