spires Posted December 13, 2011 Share Posted December 13, 2011 CREATE TABLE IF NOT EXISTS `admin_emails_desc` ( `id` BIGINT( 11 ) NOT NULL AUTO_INCREMENT , `admin_emails_id` BIGINT( 11 ) NOT NULL DEFAULT '', `lang_id` BIGINT( 11 ) NOT NULL DEFAULT '', `name` VARCHAR( 150 ) NOT NULL DEFAULT '', `subject` VARCHAR( 150 ) NOT NULL DEFAULT '', `body_content` TEXT NOT NULL , `from_name` VARCHAR( 150 ) NOT NULL DEFAULT '', `from_email` VARCHAR( 250 ) NOT NULL DEFAULT '', PRIMARY KEY ( `id` ) , FOREIGN KEY ( `admin_emails_id` ) , FOREIGN KEY ( `lang_id` ) ) ENGINE = MYISAM AUTO_INCREMENT =1 MySQL said: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' FOREIGN KEY (`lang_id`) ) ENGINE=MyISAM AUTO_INCREMENT=1' at line 11 Quote Link to comment https://forums.phpfreaks.com/topic/253074-can-you-see-the-syntax-error/ Share on other sites More sharing options...
mikosiko Posted December 13, 2011 Share Posted December 13, 2011 Can you see the syntax error ? Yes... incomplete FOREIGN KEY constraint http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html Quote Link to comment https://forums.phpfreaks.com/topic/253074-can-you-see-the-syntax-error/#findComment-1297477 Share on other sites More sharing options...
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