REGEX Help

[imperium2335]

Hi, what is the regex for this:

 

'FR'+11 digits, the first and/or the second value can also be a character – e.g. FRXX999999999

 

I have tried ^([FR]{2})*(([A-Za-z0-9]{2}\d)){11}$ and a number of other things but I can't seem to get it right.

[imperium2335]

Hi, I figured it out. Here it is incase it helps anyone else:

 

^([FR]{2})*([A-Za-z0-9]{2}\d{9})$

[joe92]

Wrong forum board

 

By the way, that regex will allow for patterns such as RF99999999999, and also 99999999999. Characters don't need to go in character classes (the square brackets) and in your case shouldn't. The beginning of your regex says

([FR]{2})*

 

That is searching for an F or an R, twice. So will match, FF, FR, RF and RR. You also say match this between zero and infinity times (the *). So it could also match '' or 'FFFRRRRRRRFRFRFFFRFRFR' - as that is F or R twice, eleven times (which is between zero and infinity). You see where I'm going with this right? You need to be matching a literal string at the beginning if it always begins with 'FR'. The regex you need is:

^FR[A-Za-z0-9]{2}\d{9}$

 

Hope this helps,

Joe

[imperium2335]

Hi, you are right. I made your adjustments and it is perfect now! thanks!

[joe92]

No problem. Don't forget to mark it as solved