Preg Replace Error

[shebbycs]

line 129- function filterBadWords($str)
{
    $result = mysql_query("SELECT badwords FROM clean") or die(mysql_error()); 
    $replacements = "*";
    
    while($row = mysql_fetch_assoc($result))
    {     
          $bad_words= $row['badwords'];
          $spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words);
          $spaced_bad_words = trim($spaced_bad_words);
          $str = preg_replace("/$bad_words | $spaced_bad_words/i", str_repeat('*', strlen($bad_words)), $str);
    }
    
    return $str;
Line 143 - }

 

I go this error "Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\xampp\htdocs\login\chatlog3.php on line 139"

[scootstah]

Does $badwords have parentheses in it?

[shebbycs]

Does $badwords have parentheses in it?

 

 

which parentheses are you saying  this

 

"$spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words);"

 

or

 

"$str = preg_replace("/$bad_words | $spaced_bad_words/i", str_repeat('*', strlen($bad_words)), $str);"

 

 

[scootstah]

I'm talking about the value of $bad_words.

[shebbycs]

I'm talking about the value of $bad_words.

 

 

$bad_words= $row['badwords'];

 

 

you means this one?

[scootstah]

Yes...

 

When you do "echo $bad_words" what do you get?

[ManiacDan]

ANY Variable included inside a regular expression MUST be run through preg_quote first.  $badWords obviously has parens in it.

 

Also, why are you doing that preg_replace on spacedBadWords?  What's the goal there?  One space after every letter?  Are you sure that's what you're getting?

[shebbycs]

ANY Variable included inside a regular expression MUST be run through preg_quote first.  $badWords obviously has parens in it.

 

Also, why are you doing that preg_replace on spacedBadWords?  What's the goal there?  One space after every letter?  Are you sure that's what you're getting?

 

 

actually my first example i had done like this

 

 function filterBadWords($str)
{
    $result = mysql_query("SELECT badwords FROM clean") or die(mysql_error()); 
    $replacements = "*";
    
    while($row = mysql_fetch_assoc($result))
    {
          $str = eregi_replace($row['badwords'], str_repeat('*', strlen($row['badwords'])), $str);
    }  
    
    return $str;
}

 

 

but the problem is for example i take suck word it can banned  capital letter or small letter of suck but when s u c k(white space included) the word still there

 

 

and im had done example using

 

<?php
function filterBadWords($str) {
    
    $replacements = "*";
    $bad_words_array = array("chit","poop","shat","chits");
    
    foreach($bad_words_array as $bad_words) {
    $spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words);
    $spaced_bad_words = trim($spaced_bad_words);
    
          $str = preg_replace("/$bad_words|$spaced_bad_words/i", str_repeat('*', strlen($bad_words)), $str);
    }  
    
    return $str;
}

$text = "I have to deal with a whole pile of chit dealing with you. Even C H I T will work too.";
echo filterBadWords($text);
?>

 

 

and the output is  I have to deal with a whole pile of ****dealing with you. Even **** will work too. but the works that ones is using foreach and array as for me im using database and while statement and im trying to matching but could not get it this is my problem

[shebbycs]

Yes...

 

When you do "echo $bad_words" what do you get?

 

 

i got this error :

 

fucksuckassbastardf u c kbitchbuttdickcockgayjerklesbianpenispussysexshitsh!tsluttitvaginab!+chb!tchbi+chmasturbateshi+sh!+boobtesticlebreastpornp0rncoak:)

Warning: preg_replace() [function.preg-replace]: Compilation failed: unmatched parentheses at offset 1 in C:\xampp\htdocs\login\chatlog3.php on line 140

aasetanhisihatfukkacakwtftestis

 

 

 

this is my database

 

[shebbycs]

 function filterBadWords($str)
{
    $result = mysql_query("SELECT badwords FROM clean") or die(mysql_error());
    $replacements = "*";
    
    while($row = mysql_fetch_assoc($result))
    {     
          $bad_words_array = array($row['badwords']);
          $spaced_bad_words = preg_replace("/(.)/i", "\${1} ", $bad_words_array);
          $spaced_bad_words = trim($spaced_bad_words);
          $str = preg_replace("/$bad_words_array|$spaced_bad_words/i", str_repeat('*', strlen($bad_words_array)), $str);
    }

    return  $str;
}


This is the new one that im try to recode surprisely the code works only the problem is the word cannot fillter ;(  Iam don know why it cannot filter