Skylight_lady Posted January 5, 2012 Share Posted January 5, 2012 Hi Guys, here is a jquery/ajax code whichever it is. I took this from a website as it's gallery looked good and different to the rest. It's jquery code is listed below: typeof(myscript)!="object"&&(myscript={}); myscript.galleryPromo=function(){ $(".enable-gallerypromo").each(function(f){ var d=$(this).attr("data-options"); var a={el:$(this),imagepath:myscript.util.getoptions({opts:d,val:"imagepath"}),type:myscript.util.getoptions({opts:d,val:"type",def:"hover"}),length:$(this).find(".gallery-thumbs li").length,thickbox:myscript.util.getoptions({opts:d,val:"thickbox"})}; var h=0; var e=0; var c=false; var b=$(".gallery-thumbs"); var g=$(".gallery-thumbs li").length-1; if(a.length>0){ b.before('<ul class="gallery-pic"></ul>\n'); $("li",b).eq(0).addClass("on").end().mouseover(function(){if(c){var k=$(this).index(); $(".gallery-thumbs li, .gallery-pic li").removeClass("on"); $(this).addClass("on"); $(".gallery-pic li").eq(k).addClass("on")}}).each(function(n){$(".gallery-pic").append("<li></li>"); var m=$(this).find("a").attr("href"); var l=new Image(); var k=$(this).find("a").attr("rel"); var o=$(this).find("img").attr("src"); var q=o.split("/"); var p=$(this).find("a").attr("title"); q[5]=a.imagepath; o=q.join("/"); $(l).bind("load",function(s){$(".gallery-pic li").eq(n).append('<a href="'+m+'" class="image-'+n+'" ><img src="'+o+'" alt="'+p+'" /><div class="gallery-details"><h4>'+p+'</h4><p class="gallery-count">'+k+"</p></div></a>"); if(n==g){ c=true; $(".gallery-pic").find("li:first-child").addClass("on")}}).error(function(){}).attr("src",o)})}})}; How do i change this to make the image path as my desired location? If you need more information please let me know and i can provide this or an address to their website if desired. I just couldn't figure out how they are getting these images to show. Quote Link to comment https://forums.phpfreaks.com/topic/254380-image-gallery-jquery-help/ Share on other sites More sharing options...
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